Problem 2: A motorcycle is slowing down uniformly, with a constant acceleration. The motorcycle covers 1000 m in 80 sec. The motorcycle then covers the next 1000 m in 120 sec. a) What is the acceleration of the motorcycle? Answer: 0.042 m/sec² b) What is the initial speed of the motorcycle? Answer: 14.2 m/sec c) What is the final speed of the motorcycle? Answer: 5.8 m/sec t = 0 sec Vo Motorcycle At₁ = 80 sec ā x = 1000 m At₂ = 120 sec x = 2000 m x

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Introduction
Section: Chapter Questions
Problem 45P: In Figure P1.49, find (a) the side opposite , (b) the side adjacent to . (c) cos , (d) sin , and (c)...
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Problem 2:
A motorcycle is slowing down uniformly, with a constant acceleration. The motorcycle covers
1000 m in 80 sec. The motorcycle then covers the next 1000 m in 120 sec.
a) What is the acceleration of the motorcycle? Answer: 0.042 m/sec²
b) What is the initial speed of the motorcycle? Answer: 14.2 m/sec
c) What is the final speed of the motorcycle? Answer: 5.8 m/sec
t = 0 sec
Vo
Motorcycle
At₁ = 80 sec
à
x = 1000 m
At₂ = 120 sec
15
x = 2000 m
X
Transcribed Image Text:Problem 2: A motorcycle is slowing down uniformly, with a constant acceleration. The motorcycle covers 1000 m in 80 sec. The motorcycle then covers the next 1000 m in 120 sec. a) What is the acceleration of the motorcycle? Answer: 0.042 m/sec² b) What is the initial speed of the motorcycle? Answer: 14.2 m/sec c) What is the final speed of the motorcycle? Answer: 5.8 m/sec t = 0 sec Vo Motorcycle At₁ = 80 sec à x = 1000 m At₂ = 120 sec 15 x = 2000 m X
x = xót vót tật, ở = To +ất, v = vỏ +2āA,t=i
+
-b+√b²-4ac
2a
Transcribed Image Text:x = xót vót tật, ở = To +ất, v = vỏ +2āA,t=i + -b+√b²-4ac 2a
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