Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- Two wastewater streams A and B, having an identical ultimate BOD are getting mixed to form the stream C. The temperature of the stream A is 20 °C and the temperature of the stream C is 10 °C. It is given that • The 5-day BOD of the stream A measured at 20 °C=50 mg/l • BOD rate constant (base 10) at 20 °C-0.115 per day Temperature coefficient = 1.135 The 5-day BOD (in mg/l, up to one decimal place) of the stream C, calculated at 10 °C, is ●arrow_forwardWastewater Engineering civil engineering (10)arrow_forwardIn the lead content analysis of a wastewater sample, 50.00 mL of the original sample was taken and diluted with 150.00 mL deionized water. The diluted sample was found to have a lead content of 17.8 ppb. What is the lead content (in ppb) of the original wastewater sample? DENSITY VALUES AT 25°C Ethanol: 0.789 g/mL Acetic Acid: 1.05 g/mL Water: 0.997 g/mLarrow_forward
- A tank contains (1000) liter of brine with (15) kg of dissolved salt. Pure water enters the tank as a rate of (10) liter/min. The solution is kept thoroughly mixed and drawn from the tank at the same rate; find the amount of salts at any time.arrow_forwardEnter T next to the following true statements and F next to the false statements. Settling of suspended solids in secondary clarifiers is typical of Type II sedimentation. Thickening prior to digestion is common in many wastewater treatment plants because it reduces the size needed for the digester. Based on a temperature of 30°C, a design mean cell residenee time of about 20 days would be reasonable for a completely-mixed anaerobic digester without recycle. A volatile suspended solid is defined as an organic solid that can be oxidized to CO2 (g) at 250°C. The theoretical yield coefficient can be estimated from the observed yield coefficient if the specific growth rate constant is known. Air flotation would likely be more efficient for thickening waste activated sludge than primary sludge, while the opposite would be true for gravity thickening. The net mass of cells produced in the activated sludge process equals the total cell mass synthesized minus the cell mass wasted as waste…arrow_forwardThe following data on the substrate removal rate and the substrate concentration is available for wastewater treatment (S) mol Rate, r (mol/min) 0.04 0.57 0.06 1.05 0.8 2.32 0.10 3.00 0.12 4.68 0.14 5.42 2.0 5.78 Estimate the value of substrate removal constant Km and the value of Vmaxarrow_forward
- In a BOD test, 5 ml of wastewater (with no dissolved oxygen) is diluted with 295 ml of water containing 8.5 mg/1 of dissolved oxygen. After 5 days incubation at 25°C, the dissolved oxygen content of the mixture is 5 mg/1. Temperature coefficient can be taken as 1.047 and BOD rate constant is 0.23 per day (base e) at 20°C. The ultimate biochemical oxygen demand of the wastewater isarrow_forward1. The following information is provided for an activated sludge system design: Parameter Symbol Value Units Flow rate Q 10000 m³/d Influent BOD So 150 mg/L Effluent BOD S 2 mg/L Hydraulic residence time Ꮎ 4 hr Mean cell residence time Oc 6 d Maximum specific growth rate μm 3 1/d Half saturation constant Ks 40 mg/L Yield coefficient Y 0.5 Endogenous decay coefficient b 0.08 1/d Death rate coefficient γ 0.04 1/d Determine: a) The aeration tank biomass concentration (X) in mg/L b) The aeration tank oxygen requirement in kg/d c) The rate of biomass wasting in kg/darrow_forwardQ- If the BOD3 of a wastewater sample is 75 mg/L and reaction rate constant k (base e) is 0.345 per day, find the amount of BOD remaining in the given sample after 10 days.arrow_forward
- In a BOD test, the amount of organic matter remaining in the wastewater was measured at certain time intervals, instead of measuring the dissolved oxygen content. The amount of organic matterremaining after 4 and 9 d was measured as 52.86 mg/L and 8.11mg/L, respectively. Calculate the ultimate BOD and BOD rate constant k for the wastewater.arrow_forwardQuestion 8A 200 g/l solution of common salt was discharged into a stream at a constant rate of 25l/s. The background concentration of the salt in the stream water was found to be 10 ppm. At a downstream section where the solution was believed to have been completely mixed, the salt concentration was found to reach an equilibrium value of 45 ppm. Estimate the discharge in the stream.arrow_forward
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