Problem 1: Two parallel plates are charged with +Q and -Q respectively as shown in the figure, where Q = 37 nC. The area of each plate is A = 0.015 m2. The distance between them is d= 6.2 cm. The plates are in the air. d +Q -Q Part (a) With the information given, write the equation of the capacitance in terms of ɛ0. A, d. C= 20 A/d v cCorrect! Part (b) Solve for the numerical value of C in pF. V Correct! C= 2.14 Part (c) With the information given, express the potential difference across the capacitor in terms of Q and C. / Correct! AV = Q/C Part (d) Solve for the numerical value of AV in V. AV = 1.7* 10(-8) AV = 1.7E-S X. Part (e) If the charges on the plates are increased to 2Q, what is the value of the capacitance C in pF? C = sin() cos() tan() 7 8 HOME cotan() asin() acos() E 4 5 6. atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END + O Degrees O Radians vol BACKSPACE DEL CLEAR Part (f) If A is then increased to 2.4, d is decreased to d/4, what is the value of the capacitance C in pF? 1 1'0

Problem 1: Two parallel plates are charged with +Q and -Q respectively as shown in the figure, where Q = 37 nC. The area of each plate is A = 0.015 m2. The distance between them is d= 6.2 cm. The plates are in the air. d +Q -Q Part (a) With the information given, write the equation of the capacitance in terms of ɛ0. A, d. C= 20 A/d v cCorrect! Part (b) Solve for the numerical value of C in pF. V Correct! C= 2.14 Part (c) With the information given, express the potential difference across the capacitor in terms of Q and C. / Correct! AV = Q/C Part (d) Solve for the numerical value of AV in V. AV = 1.7* 10(-8) AV = 1.7E-S X. Part (e) If the charges on the plates are increased to 2Q, what is the value of the capacitance C in pF? C = sin() cos() tan() 7 8 HOME cotan() asin() acos() E 4 5 6. atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END + O Degrees O Radians vol BACKSPACE DEL CLEAR Part (f) If A is then increased to 2.4, d is decreased to d/4, what is the value of the capacitance C in pF? 1 1'0