Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg. The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.1818 s, the position and velocity of the block are x(0.1818 s) -0.08836 m v(0.1818 s) = 0.9604 m/s Part (a) What was the position, in meters, at t= 0.00 s? x(0.00 s)=1 m Part (b) What was the velocity, in meters per second, at t= 0.00 s?

icon
Related questions
Question

Needs Complete typed solution with 100 % accuracy.        

Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg.
The block undergoes SHO (simple harmonic motion) with no friction. At time t= 0.1818 s, the position and velocity of the block are
Part (a) What was the position, in meters, at t= 0.00 s?
x(0.00 s) = 1
m
x(0.1818 s) = -0.08836 m
v(0.1818 s) = 0.9604 m/s
Part (b) What was the velocity, in meters per second, at t = 0.00 s?
Transcribed Image Text:Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg. The block undergoes SHO (simple harmonic motion) with no friction. At time t= 0.1818 s, the position and velocity of the block are Part (a) What was the position, in meters, at t= 0.00 s? x(0.00 s) = 1 m x(0.1818 s) = -0.08836 m v(0.1818 s) = 0.9604 m/s Part (b) What was the velocity, in meters per second, at t = 0.00 s?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer