Problem 1: Load Distribution The diagram is to support a 100 mm thick concrete slab. 5.8 kPa of dead load and 2.1 kPa of live load will be overlaying on the slab. The following is the cross-section of the beams: AB, GH = 250mm X 450mm AG, BH = 250mm X 450mm CD, EF = 250mm X 550mm a) Self weight = (0.25x0.55x5.4) x 15 = 11.1375 kN-A Tributary area = 5.4x1.25+5.4x1.5 =14.85m^2 Self load = (14.85x0.1) x 15 B = 22.275KN Dead load =14.85x5.8 =86.13KkN Total dead load =A+B+C - 110 54 5.4m - - 3m 2.5m 3m Determine the following if the unit weight of concrete is 15 kN/m3 a. b. C. b) Live load Dead loads acting on beam EF. Live load acting on beam CD. Dead load acting on girder AG. = 14.85x2.1 = 32. 185 KN Total live load = 32.185 c) Self weight = (0.25x0.45x8.5) x 15 = 34.425 kN-A Tributary area = 2.7x8.5 = 22.95m^2 Self load = (22.95x0.1) x 15 = 34.425kN-B Dead load = 22.95x5.8 = 133.11 KN-C Total dead load = A + B + C =161.88 kN =I ald

Can you solve this in a different way without using mohrs formula

The maximum deflection for the cantilever-beam below is no more than 0.03m.Macaulay’s method of double integration should be used to determine the second moment of area of the beam cross-section (I) (Please let's the final unit be in mm^4 and also provide a final check)E = 200 GN/m2  can someone please answer this question in detail who is confident in this topic with step-by-step calculations pls.  I've asked this question twice now and I've gotten different answers each time so I'm at a bit of a loss. (Pls don't respond to this if you have already responded previously) Thank you

Please solve fully with diagrams as needed and for all parts of the question. Question:  a) What is deflected shape of the beam? b) Find dispacement of beam at point B using moment-area method. c) Find displacement of beam at point B using Castiglianos theorem. Assume EI is constant for all