Problem 1: For the system shown below. 4 cos(2m 1000 t) 10 cos(2n 100, 10 cos(2 10,000 t) A. Find the value of n that will produce 100% modulation. B. Write the equation for $(t). C. Write the equation for $( f).

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Q: 2. Find 1₁, 12 and 13. 1522 M 30V +1 52 SI₁ W 12 30 18 12_2 > 13 302 W 2012 2052

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Q: Item #: For the circuit below, find the current I. j 62 ll HE -j22 j22 12 -j22 j42 24 Vac -j20…

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Q: V1 -100V R1 1000 C1 0.001FF

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Q: Refer to figure. Determine ID. Si Si +20 Vo 14 IR Ip 5.6 kQ O24.4 mA O OA O 12.2 mA O 33.3 mA V₂

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Q: calculate this in details with explanation Log 1.0025 5/3 = 12t, what is t?

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Q: What is the value of I? A) 0.1 A B) IA C) -1A 1A(1 70 IA D) -2 A E) 0 A

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Q: Question 10 If le is 100.2mA and Ic is 100mA, then lb is O 0.2mA O 200.2mA O 0.01mA O 200mA

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Q: Express 0.000000001 W as nW O 10 W O 1 nW O 100 nW O 001 nW

A: Expression of power is given 0.000000001 W.

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Q: Determine the base of the numbers for the following operation to be correct 45+20=105 *

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.