Problem 1) A statistical process control monitoring system samples the inside diameter of ball bearing every hour. Measurements were taken every hour for 25 hours. The target thickness, 7, is the average. 0.992 1.015 0.988 0.996 1.015 1.000 0.989 0.994 1.018 0.997 1.020 1.007 1.006 0.982 1.001 0.992 1.020 0.993 0.978 0.984 0.990 1.015 0.983 MANE
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- Spacers are manufactured to the mean dimension and tolerance shown in Figure 29-12. An inspector measures 10 spacers and records the following thicknesses: 0.372" 0.376" 0.379" 0.375" 0.370" 0.373" 0.377" 0.378" 0.371" 0.380" Which spacers are defective (above the maximum limit or below the minimum limit)? All dimensions are in inches.Read the setting of the metric vernier micrometer scale graduated in Figure 41-1 in 0.001mShortleaf Pines. The ability to estimate the volume of a tree based on a simple measurement, such as the diameter of the tree, is important to the lumber industry, ecologists, and conservationists. Data on volume, in cubic feet, and diameter at breast height, in inches, for 70 shortleaf pines was reported in C. Bruce and F. X. Schumacher’s Forest Mensuration (New York: McGraw-Hill, 1935) and analyzed by A. C. Akinson in the article “Transforming Both Sides of a Tree” (The American Statistician, Vol. 48, pp. 307–312). The data are provided on the WeissStats site. a. obtain and interpret the standard error of the estimate. b. obtain a residual plot and a normal probability plot of the residuals. c. decide whether you can reasonably consider Assumptions 1–3 for regression inferences met by the two variables under consideration.
- One operation of a mill is to cut pieces of steel into parts that will later be used as the frame for front seats in an automobile. The steel is cut with a diamond saw and requires the resulting parts to be within 10.005 inch of the length specified by the automobile company. Data are collected from a sample of 50 steel parts and are shown in the following table. The measurement reported is the difference in inches between the actual length of the steel part, as measured by a laser measurement device, and the specified length of the steel part. For example, the first value, -0.003, represents a steel part that is 0.003 inch shorter than the specified length. Complete parts a through c Click the icon to view the data table. a. Construct a frequency distribution Difference in Length -0.005 but less than -0.003: -0.003but less than -0.001 -0.001but less than 0.001 0.001but less than 0.003 0.003but less than 0.005 Frequency Difference Between Actual and Specified Lengths 0.002 0 -0.003…Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radius of bearing is very important for its successful functioning. To check the variability in the bearing radius, the company randomly selected ten bearings and measured the radius, the result of which is as shown in the table below. #no Nominal radius (cm) #no Nominal radius (cm) 1 2.70 6 2.59 2 2.65 7 2.73 3 2.75 8 2.64 4 2.55 9 2.88 5 2.76 10 2.83 Calculate the sample standard deviation for the above data. Construct a box plot and check whether there is any outlier data in the data distribution. Based on the comparison between the mean and the quartile, identify the shape of the data distribution. Calculate the 65th percentile and interpret the result. What is the range of the data distribution? Explain its meaning.Which EWMA chart below will yield ARL performance most close to that of cusum chart with k=1/2 and h=5? a. L=2.814, lamda=0.10 b. L=2.615, lamda=0.05 c. L=2.998, lamda=0.25 d. L=3.054, lamda=0.40 e. L=2.962, lamda=0.20
- In a Ni-Cd battery, a fully charged cell is composed of nickelic hydroxide. Nickel is an element that has multiple oxidation states. Assume the following proportions of the states: Nickel Charge Proportions Found 0 0.17 +2 0.34 +3 0.33 +4 0.5-0.34 Determine the mean of the nickel charge. Please enter the answer to 2 decimal places.A die was rolled 360 times and the results were: No. of Spots (outcomes) Frequency 1 54 2 70 3 58 4 62 5 50 6 66 Is the die balanced at a = 0.05? Determine the tabular value. OA. 18.5476 OB. 11.0705 O C. 12.5916 OD. 16.74Roman, a health data officer, was tasked to create a report describing the height of all the children ages 12-15 years in a small town in Rome. He measured the height of all the 37 children (ages 12-15 years) in that small town. Answer the table showing the number and percentage of children ages 12 to 15 years according to sex. Sex f Rel f Male <2 decimal places> Female <2 decimal places> Σf <2 decimal places>
- The following table contains measurements (in millimeters) of the diameter for a component used in surgeries. Samples of three were taken at approximately one to two hour intervals. Construct the X-bar and Range charts’ control limits (LCL and UCL) for the diameter and answer 4 questions. Observation number Sample 1 2 3 1 7 8 9 2 8 6 8 3 7 8 8 4 8 8 8 1/4) What are the control limits for the X-bar chart? 2/4) What are the control limits for the Range chart? A new sample is obtained with the following measurements (in mm): 6 8 9 3/4) What does the X-bar chart indicate for the new sample? (Cant answer, the process is out of control, or the process is in control?) 4/4) What does the Range chart indicate for the new sample? (Cant answer, the process is out of control, or the process is in control?)A new machine has just been installed to produce printed circult boards. One of the critical measurements is the thickness of the resistance layer. The quality control inspector randomly selects five boards each half-hour, measures the thickness, and records the results. The measurements (in millimeters) for the period 8:00 a.m. to 10:30 a.m. follow. Thickness (millimeters) Time 2 3 4 5 8:00 87.3 87.5 88.0 87.1 87.0 8:30 86.9 88.5 87.6 87.5 87.4 9:00 87.8 88.5 86.9 87.4 88.1 9:30 86.0 88.0 87.2 87.6 87.1 10:00 86.8 86.8 86.8 87.2 87.3 10:30 88.0 86.2 87.3 87.2 87.9 I Click here for the Excel Data File a. Determine the control limits for the mean and the range. (Leave no cells blank - be certaln to enter "O" wherever requlred. Round your answers to 2 decimal places.) Mean of the sample means LCL UCL Mean of the sample ranges LCL UCL =Suppose the lengths of human pregnancies are normally distributed with µ = 266 days and o= 16 days. Complete parts (a) and (b) below. (Type integers or decimals.) A. The proportion of human pregnancies that last less than B. The proportion of human pregnancies that last more than days is days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts less than B. The probability that a randomly selected human pregnancy lasts more than (b) The figure to the right represents the normal curve with µ = 266 days and o = 16 days. The area between x = 280 and x = 295 is 0.1558. Provide two interpretations of this area. days is days is Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or…