Problem 1: A concrete dam retaining water is shown in the figure below. The head of water on the upstream side (with a vertical face) is 14 m while it has 4m deep of water on the downstream side. Consider a uniformly varying uplift pressure from a 75% effect for both sides. The concrete weighs 23.50 kN/m3 and there's a 0.75 coefficient of friction between the soil and dam foundation. Using the following data: b= 4m, B=20m, z=2.5m, a=3m, c=2m, d=2m, and the slope of the inclined portion at the upstream face is 1H:1.50V while that of the downstream portion is 2.50H:4V Determine the a. Total vertical reaction at the base of the structure b. Overturning moment c. Resisting moment d. The line of action of the total vertical reaction from the heel e. Factor of safety against overturning Factor of safety against sliding g. Foundation pressure at the heel h. Foundation pressure at the toe f. Figure: b a d N

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Hi dear tutor, please help me continue to solve this question. I have already solved (a), (b), (c), (d); I attached the solution along with the question for easy reference. Please help me solve (e), (f), (g), (h) only. I would appreciate your assistance and thank you so much!

Problem 1: A concrete dam retaining water is shown in the figure below. The head of water on the
upstream side (with a vertical face) is 14 m while it has 4m deep of water on the downstream side.
Consider a uniformly varying uplift pressure from a 75% effect for both sides. The concrete weighs
23.50 kN/m3 and there's a 0.75 coefficient of friction between the soil and dam foundation. Using the
following data: b= 4m, B=20m, z=2.5m, a=3m, c=2m, d=2m, and the slope of the inclined portion at the
upstream face is 1H:1.50V while that of the downstream portion is 2.50H:4V Determine the
a. Total vertical reaction at the base of the structure
b. Overturning moment
c. Resisting moment
d. The line of action of the total vertical reaction from the heel
e. Factor of safety against overturning
Factor of safety against sliding
g. Foundation pressure at the heel
h. Foundation pressure at the toe
f.
Figure:
b
a
d
В
N
Transcribed Image Text:Problem 1: A concrete dam retaining water is shown in the figure below. The head of water on the upstream side (with a vertical face) is 14 m while it has 4m deep of water on the downstream side. Consider a uniformly varying uplift pressure from a 75% effect for both sides. The concrete weighs 23.50 kN/m3 and there's a 0.75 coefficient of friction between the soil and dam foundation. Using the following data: b= 4m, B=20m, z=2.5m, a=3m, c=2m, d=2m, and the slope of the inclined portion at the upstream face is 1H:1.50V while that of the downstream portion is 2.50H:4V Determine the a. Total vertical reaction at the base of the structure b. Overturning moment c. Resisting moment d. The line of action of the total vertical reaction from the heel e. Factor of safety against overturning Factor of safety against sliding g. Foundation pressure at the heel h. Foundation pressure at the toe f. Figure: b a d В N
b=4m
2.9.
Yosne = 23.5 KN/m?
g,81KN/m?
3.
Wt of dift ponhn of dem :-
114:4m
h=14m
W= 20×2,バスル 23.5 'S 1175KN
2.8-
1.5V
l2=x2x 323.5= 70.5KN.
1. Sm
(4+ 2.9 - 25)×1入り×23,バニ1353.6kM
", 2. sH
%3D
2m
x (1442.9-2.5)x 1x9 x23.5=1522.8KN
'neet
2om
Ikly =
Toe
Pv (vent preme due to waler) - (14-S.5)X5x3.81X1
+ (5+3)x3 *98X1
- 65 2.37 KN (Py = 416,93 KN ePvz =235i4kN)
@) -'. Total vert neachina l175+705+1353.6+1522-8+G52-37
4774.3 KN
x14 X14 x981=
961.4KN
(b) Pu
M.
Pu x /3 = 4486.5 KNm
Wix L.AL + laz XLA, t llg xLA, + laly xLAy tPuLAy
C) MA =
+ 70.5x(2+9+4+ 2/3 ) +1353.6x249 +4/2) +
LAS
+1522.8x (2+ 3x9) + Pv, x LAvi tPvz
1175x 20
42633. 7 +416. 9 3 x (2 +3+4++235.4(2+9+4
=42633.7 +7296.28 + 4190.12
) Me
54120 KNm
う
3 x3x(2+%½) +
MR
(d) Line of Achanago-
Tver Rechm
3 ×3 + x3×2
54120.
= 20-
4774.3
= 8.66m
Shot on realme &
2021/12/09 08:54
Transcribed Image Text:b=4m 2.9. Yosne = 23.5 KN/m? g,81KN/m? 3. Wt of dift ponhn of dem :- 114:4m h=14m W= 20×2,バスル 23.5 'S 1175KN 2.8- 1.5V l2=x2x 323.5= 70.5KN. 1. Sm (4+ 2.9 - 25)×1入り×23,バニ1353.6kM ", 2. sH %3D 2m x (1442.9-2.5)x 1x9 x23.5=1522.8KN 'neet 2om Ikly = Toe Pv (vent preme due to waler) - (14-S.5)X5x3.81X1 + (5+3)x3 *98X1 - 65 2.37 KN (Py = 416,93 KN ePvz =235i4kN) @) -'. Total vert neachina l175+705+1353.6+1522-8+G52-37 4774.3 KN x14 X14 x981= 961.4KN (b) Pu M. Pu x /3 = 4486.5 KNm Wix L.AL + laz XLA, t llg xLA, + laly xLAy tPuLAy C) MA = + 70.5x(2+9+4+ 2/3 ) +1353.6x249 +4/2) + LAS +1522.8x (2+ 3x9) + Pv, x LAvi tPvz 1175x 20 42633. 7 +416. 9 3 x (2 +3+4++235.4(2+9+4 =42633.7 +7296.28 + 4190.12 ) Me 54120 KNm う 3 x3x(2+%½) + MR (d) Line of Achanago- Tver Rechm 3 ×3 + x3×2 54120. = 20- 4774.3 = 8.66m Shot on realme & 2021/12/09 08:54
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