Problem 03.-Incomplete Design Examine the following diagram. A utility firm is planning on installing a new pole to shorten the length of the span between poles P1 and P3. This new pole, P2, will be along the same bearing as the line coming in to P1 from the west, and is planned to be a distance of 200.00' from P3 as shown. You are tasked with filling in the missing dimensions on this drawing. P1 N 65° 12' 46" E 468.72¹ N 86° 27' 53" E Part a. Determine the bearing from P2 to P3. Part b. Determine the distance from P1 to P2. Part c. 1 - P2 0.00' 200.0 P3 Using the distance in Part b., check the angle used to determine the bearing in Part a.

Problem 03.-Incomplete Design Examine the following diagram. A utility firm is planning on installing a new pole to shorten the length of the span between poles P1 and P3. This new pole, P2, will be along the same bearing as the line coming in to P1 from the west, and is planned to be a distance of 200.00' from P3 as shown. You are tasked with filling in the missing dimensions on this drawing. P1 N 65° 12' 46" E 468.72¹ N 86° 27' 53" E Part a. Determine the bearing from P2 to P3. Part b. Determine the distance from P1 to P2. Part c. 1 - P2 0.00' 200.0 P3 Using the distance in Part b., check the angle used to determine the bearing in Part a.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

SITUATION. A plate-and-angle girder is fabricated by bolting the short legs of four 125 x 75 x 13 mm angles to a web plate 1000 mm x 10 mm to form a section 1020 mm deep. Cover plates each 300 mm x 10 mm are then bolted to the flange angles making the overall height of 1040 mm. 300 10 20.7 729² +13 N.A. 1040 1020 Properties of 125 x 75 x 13 mm angle: Ix = 3.82 x 106 mm* A = 2430 mm² Iy = 1.04 x 105 mm* y = 39.6 mm Bolt Ultimate Shear Stress, Tuv = 100 MPa Bolt Ultimate Bearing Stress, Tub = 200 MPa 1. Determine the moment of inertia of the section about NA. 2. Determine the pitch for the 22 mm-dia bolts, connecting the angles to the web plate at a section where the ultimate shear load, Vu = 450 kN. 3. Determine the pitch for the 22 mm-dia bolts, connecting the angles and the cover plates at a section where the ultimate shear load, Vu = 450 kN. x = 20.7 mm
Not the ȳ. I NEED THE y for the top and bottom flange? how did they get the values 4.917 and 11.58
Notice: This is only for REVIEW PURPOSES, this is NOT GRADED. What force P must be applied to the wedges shown to start them under the block. The angle of friction for all contact surfaces is 10°. W= 1,500 N The angles in the image are both 30° Options: A. 800.98 N B. 132.0 N C. 321.32 N D. 761.57 N E. Other answer
Truss 2KN and 60 degrees
Evaluate the integral of ez+12zdz O e+1+ C e'r +C O e1/ln2 + C O2ze + C
The possible location of shear centre of the channel section, shown below, is PQ ¡R S
Ure the Method of Uirtuat work to determine the uertical OL JoInts B and D of the Jteel truss. dupcacement 15KN HSEN .F um E = 200 GPa A 5480mm %3D
P.T, P.I, P.C are the basic requirements for setting a Vertical . curve True O False O
5:16 4G ll 34% Based on the the truss given, what is the value of force acting on member AD? * CG00 KN 240 KN D lem 58.13° A 24m 12m Dr I2m 300 KAN 394.33 KN 375 KN 493.33 KN 357 KN Other: What is the value of the force acting on member CD? * O 537 KN 473 KN 375 KN 386 KN Other:
Resolve each force acting on the gusset plate into its and y components, and .express each force as a Cartesian vector F= 650 N %3D 3] F= 750 N 45° F = 900 N F1 = (-900i} N ; F2 = {-530i - 530j} N; F3 = {520 i - 390j)} N %3D F1 = (900i} N ; F2 = {530i + 530j} N ; F3 = {520 i - 390j)} N F1 = (900i} N; F2 = {530i - 530j} N ; F3 = {520 i + 390j)} N F1 = (900i} N ; F2 = {530i - 530j} N ; F3 = {390 i + 520j)} N %3D
d] Draw the deflected shape of the beam below
Solve the attachment