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A: Given vector pairs A) A = -2.00i + 6.00j and B = 2.00i - 3.00j B) A = 3.00i + 5.00j and B = 10.00i…
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A: Given:a = 2.0 i^ + 5.0 j^ ................eq(1)b = 3.0 i^ + 9.0 j^ ................eq(2)
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Q: Express the force as a Cartesian vector.
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A: Given:P→ = 32 u, 90° North of EastR→ = 12 u, 45° North of East
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A: given that,a=6b=12FAB=12 lb
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A: Given that,θ= 60°F=450 N
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A: Given,Force, F = 115 i^ + 70 j^ - 170 k^ N
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Q: Find the angle between vector a and b if a 21 +j- k and b 3i - 6j + 2k
A: a→ = 2i^ + j^ - k^b→ = 3i^ - 6j^ + 2k^
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Q: if A⃗ =2i+3j+6kA→=2i+3j+6k and A⃗ =3i−4j+2kA→=3i−4j+2k, then the angle between the two vectors is
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A: Introduction : Angle between two vectors can be found by taking their dot products. Given :…
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Q: given the vector v=i+2j+k what is the angle between v and the xaxis
A: v→ = i^ + 2j^ + k^ Magnitude of vector v = (1)2 + (2)2 + (1)2= 1+4+1= 2.45
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A: I write the answer in a paper. I hope you like it.
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Q: If the F1= F2 = 40 KN determine the angle θ with y axis and o with y axis so that the resultant…
A: Given: F1 = F2 = 40 kN FR = 30 kN To determine: Angle θ Formula used: FR = F12+F22+2F1F2cosθ
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A: GIVEN: D= 2.5i^-4j^+k^
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A: 1. Given Vector A=i+2j-k B=-4i+j-2k
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A: the given vector is A=Axi^+Ayj^+Azk^
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A: Given data The first force is, F = 450 N The second force is, F1= 700 Nange made by first vector…
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A: Here given two vectors A and B. Given A= 6i+4j+2k and B= 3i-5j-3k We have to find the angle…
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Q: If A = 12 i- 16 j and B = 24 i+ 10 j, what is the direction (angle in degree) of the vector C = 2A +…
A: Given data: Two vectors A = 12i - 16j B = 24i + 10j Required: The direction of the vector C = 2A +…
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A: Given F=-5i+4j Displacement D=-2i-3j To Find Angle between vectors θ
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- Show that when A+B=C then A2+B2+2ABcos , where is the angle between vectors A and B .To get up on the roof, a person (mass 70.0 kg) places 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad with the base of ladder 2.00 m from the house. The ladder rests against a plastic rain gutter, which we can assume to frictionless. The center of ladder is 2.00 m from the bottom. The person is standing 3.00 m from the bottom. Find the normal reaction and friction forces on the ladder at its base.Fe -4i+4j+2k LB 6IN Determine the moment due to the force about point 0, expressing the moment as a Cartesian Vector.
- Figure 3 ft 4 ft 5 ft. < 1 of 1 If F₁ = {100i - 125j + 95k} lb and F₂ = {−210i + 280j + 100k} lb, determine the resultant moment produced by these forces about point O. Express the result as components of a Cartesian vector. (Figure 1) Enter the x, y, and components of the moment of force separated by commas. Mo = Submit V— ΑΣΦ 510, 1110,950 vec Provide Feedback Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining lb. ftA professional athlete tears their Achilles tendon. There are two muscles in the back of the leg that pull upward on the Achilles tendon, as shown in the image below. (The Achilles tendon is the gray part above the heel) F₂ (250 N) F, (250 N) (a) Using information from the image above, what is the magnitude of the total force on the Achilles tendon? Number (b) What is the direction of the force on the Achilles tendon in the image? Up Down Left 20% 20° RightThe slope of the 5.0 KN force F is specified as shown in the figure. Express F as a vector in terms of the unit vectors i and j. Assume a = 13, b = 6. Answer: F = ( F b i+ j) KN
- F4-12. If the two forces F F2 = {-200i + 250j + 100k} lb act at A, determine the resultant moment produced by these forces about point O. Express the result as a Cartesian vector. , = {100i – 120j + 75k} lb and 4 ft 3 ft 5 ft.The combined action of the three forces on the base at O may be obtained by establishing their resultant through O. Determine the magnitudes of R and the accompanying couple M. Assume F1 = 640 Ib, F2 = 590 lb, F3 = 690 Ib, a = 7.3 ft, b = 2.3 ft, c = 2.9 ft, and 0 = 47. F, 9. a Answers: R= i Ib M= i Ib-ftThe forces are in static equilibrium. The 140 lb force is directed along the x-axis and the 300 lb force is directed along the negative z- axis. Determine the magnitude of the unknown force, R. Z X R Ox лог 140lb A (-50, 80, 160) lb By 300 lb у
- Problem 04.096- Resultant Force and Moment of a System of Forces The structure has two frictionless pulleys around which a string is wrapped. If W=56 lb, determine a force system that is equivalent to the forces applied by the string, where this force system consists of a single force, and specify the x coordinate of the point where the force's line of action intersects the x axis. (Round the final answers to four decimal places. Do not include a minus sign in your response.) 20 in. r = 2 in. 5 in. 4 in. The value of (FR)x of the equivalent force system is The value of (Fray of the equivalent force system is lb 1. The x coordinate of the point where the equivalent force's line of action intersects the xaxis is lb-. In.Summation of Forces Forces are given; Force 1 = 12 N @ 110° Force 2 = 15 N @260° Force 3 = 5 1 - 6 in 1. Find the resultant force if they are all added? 2. What are the magnitude and angular direction of the sum of the vectors? (Dot Product) 3. F1 o F2= 4. F1 x F3 = (Cross Product)|This course Hide block The cable of the tower crane is subjected to 840 N force, the magnitude of the moment of the force F about A is. Hìnt: Determine the moment of the force 'F' in Cartesian Vector Form, then deduce the magnitude. B F = 840 N 24 m 3 m 15 m 2m 10 m