**Probability of Selecting a Male Student or a Student with an "A" Grade** In this probability exercise, we analyze a group of students based on their grades and gender. The following table summarizes the distribution: | | A | B | C | Total | |--------|----|----|----|-------| | Male | 13 | 8 | 14 | 35 | | Female | 19 | 4 | 5 | 28 | | Total | 32 | 12 | 19 | 63 | **Objective:** Determine the probability that a randomly selected student is either male or has received an "A" grade. To solve this, we need to calculate: 1. Total students who are male. 2. Total students who received an "A". 3. Use the formula for probability with "or" condition: \[ P(\text{Male or A}) = P(\text{Male}) + P(\text{A}) - P(\text{Male and A}) \] - **Total students**: 63 - **Total males**: 35 - **Total students with an "A"**: 32 - **Males with an "A"**: 13 Using the formula: \[ P(\text{Male or A}) = \frac{35}{63} + \frac{32}{63} - \frac{13}{63} = \frac{54}{63} = \frac{18}{21} \approx 0.857 \] **Conclusion:** The probability that a randomly selected student is either male or received an "A" is approximately 0.857, or 85.7%.
**Probability of Selecting a Male Student or a Student with an "A" Grade** In this probability exercise, we analyze a group of students based on their grades and gender. The following table summarizes the distribution: | | A | B | C | Total | |--------|----|----|----|-------| | Male | 13 | 8 | 14 | 35 | | Female | 19 | 4 | 5 | 28 | | Total | 32 | 12 | 19 | 63 | **Objective:** Determine the probability that a randomly selected student is either male or has received an "A" grade. To solve this, we need to calculate: 1. Total students who are male. 2. Total students who received an "A". 3. Use the formula for probability with "or" condition: \[ P(\text{Male or A}) = P(\text{Male}) + P(\text{A}) - P(\text{Male and A}) \] - **Total students**: 63 - **Total males**: 35 - **Total students with an "A"**: 32 - **Males with an "A"**: 13 Using the formula: \[ P(\text{Male or A}) = \frac{35}{63} + \frac{32}{63} - \frac{13}{63} = \frac{54}{63} = \frac{18}{21} \approx 0.857 \] **Conclusion:** The probability that a randomly selected student is either male or received an "A" is approximately 0.857, or 85.7%.