Predict the geometries of the following ions, using the VSEPR model. a. GeCl, trigonal bipyramidal tetrahedral O linear square planar octahedral O bent square pyramidal seesaw OT-shaped b. SbCle O trigonal bipyramidal O tetrahedral O linear square planar octahedral bent square pyramidal seesaw T-shaped c. CIF2- trigonal bipyramidal O tetrahedral linear square planar octahedral O bent square pyramidal seesaw OT-shaped d. BrCl4-

One property of the pi (x) bond is: The pi bond is not a hybridized bond. None of these apply to a pi bond. The pi bond results from end to end overlap of s and p orbital. The pi bond does not allow free rotation of atoms in the bond. The pi bond allows free rotations of atoms in the bond. « Previous Next » OCT 29 esc 80 F1 F2 F3 F4 F5 @ 24 1 2 4 W # 3

Which of the following molecules has a trigonal planar structure? 1. CO32- 2. SOCI2 3. H30* 4. SO32-

This is not a real molecule, A is not an element, but if it was an molecule what would the molecular geometry of atom A be?    Linear Bent Trigonal pyramidal Trigonal planar Tetrahedral

5. Sulfur hexafluoride, SF, has an octahedral geometry with all the F-S-F bond angles being 90°. In BrF5, the F-Br-F bond angle is 81.9°, while in XeF4, the F-Xe-F angle is 90°. Explain why 90.0 90.0⁰ 90.0 90.0⁰ 90.0 90 84.8° 84.8 84.8 84.8 90.0⁰ *90.0* 90.0⁰ 90.0⁰