Predict the equilibrium of the following reactions. Which of the following reaction is Keq a) Me b) d) Me i Me Å F3C Me T H H + H₂O OH Me H + MeMgBr + H₂O + H₂O + PCC HO OH Me Me BrMg-O Me Me Me HO OH X F3C CF3 HO OH H H Me Me Ketone formation is not favorable

How many different proton environments are present in each of the following compounds? A H OA= 6; B= 4; C= 4 O A= 5; B= 4; C=6 O A = 3; B= 5; C= 6 O A= 6; B= 5; C= 5 O A= 6; B= 3; C= 6 H но. ---- C CI Br

I need help identifying the unknown. I'm not sure if this IR belongs to 2-methyl-1-propanol, 2,2-dimethyl-1-propanol, or could it belong to a different alcohol?

I need help with analyzing this

1. Predict the product(s) and show the mechanism for each reaction below II. After finding the product, find how many C are there for each product and how many H signals in what integral ratio + CH3OH

Chemically equivalent or chemically non-equivalent?

Please don't provide handwriting solution

For each organic compound in the table below, enter the locant of the highlighted side chain. CH3 CH,— CH,— CH— CH, CH3 1 compound CH₂ | CH,—C− CH,—CH — CH CH3 モー CH3 CH,—CH— CH,—C— CH | CH₂ CH3 CH3 | CH3 locant of highlighted side chain 0 X S

I am confused as to how to go about solving this problem. I already split them into three distinct hydrogens: the methyl group hydrogens, the hydrogens to the farther left of the NO2 group, and the hydrogens closest to the NO2 group. For the methyl group hydrogens, I expect 1 peak, for the ones farther to the left I expect n+1 = 2+1 = 3 peaks, but for the ones nearest the NO2 group, I believe they go through complex splitting and am confused. Detailed explanation would be appreciated.