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Practice: X~ Bin(15,0.2) X is at most 8 : P(X ≤ 8) = F(8) = 1 X is exactly 8: P(X = 8) = F(8) – F(7) = = ... 3 X is at least 7 : P(X ≥ 7) = 1 - P(X ≤ 6) = 1 − F(6) = 4 X is between 4 and 7 and inclusive : P(4≤X ≤7) = F(7) - F(3) = ... :

Practice: X~ Bin(15,0.2) X is at most 8 : P(X ≤ 8) = F(8) = 1 X is exactly 8: P(X = 8) = F(8) – F(7) = = ... 3 X is at least 7 : P(X ≥ 7) = 1 - P(X ≤ 6) = 1 − F(6) = 4 X is between 4 and 7 and inclusive : P(4≤X ≤7) = F(7) - F(3) = ... :

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Practice : X Bin(15,0.2) X is at most 8 : P(X ≤ 8) = F(8) = X is exactly 8: P(X = 8) = F(8) – F(7) = 3 X is at least 7 : P(X ≥ 7) = 1- P(X ≤ 6) = 1 - F(6) = ... 4 X is between 4 and 7 and inclusive : P(4 ≤ x ≤7) = F(7) - F(3) = ...
Transcribed Image Text:Practice : X Bin(15,0.2) X is at most 8 : P(X ≤ 8) = F(8) = X is exactly 8: P(X = 8) = F(8) – F(7) = 3 X is at least 7 : P(X ≥ 7) = 1- P(X ≤ 6) = 1 - F(6) = ... 4 X is between 4 and 7 and inclusive : P(4 ≤ x ≤7) = F(7) - F(3) = ...
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