Structural Analysis
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Please answer the problem attached image. Hint: 1. a=293.27mm, b=970.63×10^6mm^4 2. 48.857×10^6mm^4
Practice Problem 1
Find the distance of the centroid of the built-up section from the bottom and its centroidal moment of
inertia along the x-axis.
Properties of C180x15 channel.
A = 1850 mm²
tw = 5.3mm
x= 13.8 mm
Properties of W250x18
A wide flange and a channel have the following properties.
Wide Flange
Channel
A = 18400 mm²
A = 6430 mm²
Ix=131x106 mmª
ly = 3.4x106 mm¹
tw = 10 mm
x =20 mm
FB = 118 MPa
A = 2270 mm²
bf= 101 mm
tw= 4.8 mm
Practice Problem 2
A built-up section fabricated by attaching a C180x15 to a W250x18 shape with 15 mm rivets as shown.
Determine the moment of inertia at the centroid of the built-up section.
tw = 12 mm
d=470 mm
Ix = 726x106 mmª
ly = 93.6x106 mmª
Ix=8.86x106 mm¹
ly= 0.405x105 mm
Ix= 22.4x106mm*
d=251 mm
tf=5.3 mm
FB = 138 MPa
5.31
251
N.A.
101
113.8
64.46
52.54
115.3
=78.26
130.80
Check your answers against the Key to Corrections found at the end of this SAS. Write your score on your paper.
Question: In Practice Problem 1 and 2, what will happen if another channel, of the same properties, is
attached to the bottom of the wide flange? What will happen to the centroid of the built-up section? Can
you just algebraically add the individual moments of inertia of the channels and the wide flange?
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Transcribed Image Text:Practice Problem 1 Find the distance of the centroid of the built-up section from the bottom and its centroidal moment of inertia along the x-axis. Properties of C180x15 channel. A = 1850 mm² tw = 5.3mm x= 13.8 mm Properties of W250x18 A wide flange and a channel have the following properties. Wide Flange Channel A = 18400 mm² A = 6430 mm² Ix=131x106 mmª ly = 3.4x106 mm¹ tw = 10 mm x =20 mm FB = 118 MPa A = 2270 mm² bf= 101 mm tw= 4.8 mm Practice Problem 2 A built-up section fabricated by attaching a C180x15 to a W250x18 shape with 15 mm rivets as shown. Determine the moment of inertia at the centroid of the built-up section. tw = 12 mm d=470 mm Ix = 726x106 mmª ly = 93.6x106 mmª Ix=8.86x106 mm¹ ly= 0.405x105 mm Ix= 22.4x106mm* d=251 mm tf=5.3 mm FB = 138 MPa 5.31 251 N.A. 101 113.8 64.46 52.54 115.3 =78.26 130.80 Check your answers against the Key to Corrections found at the end of this SAS. Write your score on your paper. Question: In Practice Problem 1 and 2, what will happen if another channel, of the same properties, is attached to the bottom of the wide flange? What will happen to the centroid of the built-up section? Can you just algebraically add the individual moments of inertia of the channels and the wide flange?
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