pplying Kirchhoff's Laws to the electrical network in the figure, the currents I,, ,, and I, are the solution of the system - 12 + I3 = 0 311 + 512 512 + 413 = 28 %3D = 26 %3D where a = 3, b = 5, c = 4, v, = 26, and v, = 28. Find the currents. %3D %3D 1 %3D 2 3 = , volts V2volts

pplying Kirchhoff's Laws to the electrical network in the figure, the currents I,, ,, and I, are the solution of the system - 12 + I3 = 0 311 + 512 512 + 413 = 28 %3D = 26 %3D where a = 3, b = 5, c = 4, v, = 26, and v, = 28. Find the currents. %3D %3D 1 %3D 2 3 = , volts V2volts

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 4PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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Current Division Method

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Applying Kirchhoff's Laws to the electrical network in the figure, the currents and I1,I2 and I3 are the solution of the system

Applying Kirchhoff's Laws to the electrical network in the figure, the currents I,, I,, and I, are the solution of the system
I2 + I3 = 0
31 +512
512 + 413
= 26
= 28
where a = 3, b = 5, c = 4, v, = 26, and v2
= 28. Find the currents.
I, =
I, =
Iz =
I3
a Q
, volts
V2 volts
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