pothesis 15. Suppose that X is a random variable about which the XUNIF(0, 1) against Ha: X~N(0, 1) is to be tested. What is the most powerful test with a significance level a = 0.05 based on one observation of X?
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- Previous Probletn Let X and Y be independent random variables. Suppose X has variance 2 and let Y have variance 5. Find Var(3X-2Y + 3). Please answer to 2 decimal places.Q1: Suppose that Y,, Y2, Y constitute a random sample from a normal distribution with known mean u and unknown variance a?. The most powerful a-level test is sued for testing Ho:a² = o versus HA: 0² = af, where af > o3. نقطة واحدة .3 3. The rejection region is given by RR = A. True B. FalseSuppose there is a claim that a certain population has a mean, H, that is different than 5. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.10 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H1, as follows. Hg: u= 5 H1: u=5 Suppose you also know the following information. The value of the test statistic based on the sample is 1.506 (rounded to 3 decimal places). The p-value is 0.132 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. Standard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.2 Step 3: Shade the area represented by the p-value. 0.1+ Step 4: Enter the p-value. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), which statement below is true? Since the p-value is less…
- A random sample of size 29 is selected from a normal population with mean = and variance = 8. Determine the probability that s? (the sample variance) is between 11.81 and 14.57. 12A researcher is testing a hypothesis of a single mean. The critical t value for a = .05 and a one-tailed test is 2.0639. The observed t value from sample data is 1.742. The decision made by the researcher based on this information is to the null hypothesis. reject not reject redefine change the alternate hypothesis into restateSuppose there is a claim that a certain population has a mean, 4, that is different than 9. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H1, as follows. Hg: 4= 9 H: u=9 Suppose you also know the following information. The value of the test statistic based on the sample is -2.044 (rounded to 3 decimal places). The p-value is 0.041 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. Standard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed 0.3+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.2+ Step 3: Shade the area represented by the p-value. 0.1+ Step 4: Enter the p-value. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), which statement below is true? O since the p-value is less…
- A random sample of 100 male employees showed that 42 are working from home while a random sample of 100 female employees showed that 63 are working from home. Are the two population proportions equal? Test at alpha=0.05. What is Ho and Ha? And what is the test statistic value for this test? Based on the test statistic value, what is your decision?Suppose there is a claim that a certain population has a mean, µ, that is different than 7. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothesis H, and the alternative hypothesis H, as follows. Hoi u= 7 H: u =7 Suppose you also know the following information. The critical values are - 1.960 and 1.960 (rounded to 3 decimal places). The value of the test statistic is 2.477 (rounded to 3 decimal places). (a) Complete the steps below to show the rejection region(s) and the value of the test statistic for this test. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. One-tailed 0.3 Two-tailed Step 2: Enter the critical value(s). (Round to 3 decimal places.) 0.2+ 0.1+ Step 3: Enter the test statistic. (Round to 3 decimal places.) 2 (b) Based on your answer to part (a), choose the correct statement. O The value of the test…200 poodles 61 are left-paued left -pawed. a random sample of In a random sample ef 220 labradores 38 are Can we conclude that the difference in The tuo sample proportions of left pawed dogs is statistically significont for x= 0.05 ?
- A statistical test is designed to show that the mean u is different from 100, state the null hypothesis (Ho) and the alternative hypothesis (Ha) to be tested.The weight of a male bald eagle has approximately a normal distribution with mean ?= 7.4 pounds and a standard deviation of ?= 1.6 pounds. Suppose we take a random sample of n=64 male bald eagles. Let X̄ be the random variable representing the mean weight in pounds of the 64 sampled male bald eagles. Let Xtot be the random variable representing sum of the weights of the 84 sampled bald eagles. a) About what proportion of male bald eagles have weights between 7.0 and 7.8 pounds? b) About what proportion of male bald eagles have weights greater than 7.8 pounds? c) About how many of the 64 sampled male bald eagles would you expect to have weight greater than 7.8 pounds? (nearest integer)? d) About how many of the 64 sampled male bald eagles would you expect to have weight between 7.0 and 7.8 pounds? (nearest integer)? e) What is the standard deviation of the distribution of X̄ (in pounds)? f) What is the standard deviation of the distribution of Xtot (in pounds)? g) What is the…Executives of a supermarket chain are interested in the amount of time that customers spend in the stores during shopping trips. The mean shopping time, μ , spent by customers at the supermarkets has been reported to be 36 minutes, but executives hire a statistical consultant and ask her to determine whether it can be concluded that μ is greater than 36 minutes. The consultant plans to do a statistical test and collects a random sample of 50 shopping times at the supermarkets. Suppose that the population of shopping times at the supermarkets has a standard deviation of 16 minutes and that the consultant performs her hypothesis test using the 0.05 level of significance.
