Poisson's ratio is defined as
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- From the shear stress - shear strain diagram shown below, all the following are true except: Shear Stress (MPa) 500 450 400 350 300 250 200 150 100 50 0. 0.2 0.4 0.6 0.8 1.2 1.4 1.6 1.8 Shear Strain (rad) Shear Stress-Strain Curve for Brass Select one: O a. Shear stress and Shear strain are 430 MPa and 1.72 rad at fracture. O b. Shear stress and Shear strain are 250 MPa and 0.05 rad at Yielding. Oc. The elastic zone ends at a shear stress of 400 MPa and shear strain of 1 rad Od. The ultimate Shear stress and Shear strain are 430 MPa and 1.72 rad.Help me please5. Please calculate the strain and stress in the following two prompts a. A 1 cm long section of tendon stretches to 1.011 cm when it is subjected to a tensile force of 40,000 N. What is the strain in this segment of tendon? @? 17 b. The section of the patellar ligament in the previous question is 0.02 m² in the cross section. What is the stress in this section of ligament as a result of 50,000 N tensile force? E = Δι 19 0 = A 1.011 cm 50000 0,02 Scoco 40000 1.25 = T % 2500000 strain N/m² on trito flox your wrist, you may notice that your
- A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lb - in per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in.in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lblb - in.in. per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.Table B2: Stress-strain data for uniaxial compression test on Sample Normal stress Uniaxial strain (%) Lateral strain (%) (MPa) 0.0 0.0000 0.0000 5.0 0.0319 -0.0150 10.0 0.0720 -0.0275 15.0 0.1025 -0.0425 20.0 0.1450 -0.0600 25.0 0.1755 -0.0725 30.0 0.2150 -0.0875 35.0 0.2455 -0.1025 41.0 0.2815 -0.1125 46.0 0.3125 -0.1209 52.0 0.3515 -0.1285 58.0 0.4000 -0.1325 (f) Based on the plotted curve, calculate the average/tangent Young's modulus and Poisson's ratio for this sample, at 50 % UCS?
- The following data are taken from a 20mm in diameter bar of length 250mm, the following results were recorded. Assume that the curve of the stress-strain diagram is linear from the origin to the first point. P (load in kN) 8(elongation in mm) 112 0.2 154 0.3 167 0.4 0.5 174 181 0.8 Determine the a. Stress at 187 kN load in MPa b. Strain at 167 kN load in mm/mm (expressed in scientific notation) c. Modulus of elasticity in MPa d. Modulus of resilience in N-mm/mm e. Modulus of toughness in N-mm/mm 234 oo OOO O0. Data was collected from the tensile test demonstration for Aluminum 6061-T6. Below are the resulting stress-strain diagrams based on the tensile test we performed. o (MPa) Al 6061-T6 Stress-Strain Curve o (MPa) 350 320 300 250 200 150 100 50 0 Estimate 0 0.05 0.1 0.15 ε (mm/mm) 300 270 250 220 200 150 140 100 a) The modulus of Elasticity, E b) The yield stress, d, using the 0.2% offset method c) The strain at failure, & failure d) The modulus of resilience (approximately!) 50 0 0 Al6061-T6 Stress-Strain Curve, Magnified N 0.0032 0.002 0.004 0.006 0.008 € (mm/mm) The right diagram shows the magnified elastic region of stress-strain diagram to enhance the details.Stress Vs Strain on Aluminium 120.00 100.00 80.00 60.00 40.00 20.00 0.00 -20.00 -40.00 Strain (mm/mm) Stress (MPa) 0000'0 0.0105 0.0211 0.0316 0.0422 0.0527 0.0633 0.0738 .0854 0.0855 0.0856 6.0857
- 11)The total volume of inherent strains in longitudinal direction is Vy = Kq. Here what is the unit of q? O Joule (J) O Joule per unit time (J/s) O Joule per unit length (J/m) O Joulexsecond (J-s)b) A 1.25 m long cable has a diameter 3.50 mm with a Young's Modulus, E, of 9.75 x 10⁹ N/m². When the wire is placed under tension, it experiences a stress of 202.52 x 106 N/m², the length of the cable extends by 36.35 mm. Calculate the force that the cable experiences under tension and the strain energy density (U/V) due to deformation. Give your answers in newtons (N) to 2 decimal places for the force; and in joules per cubic metre (J/m³) for the strain energy density to 2 decimal places. Assume the cable is solid and the material is homogeneous. c) Figure Q1c shows a bracket on rollers that allow the bracket to move along a beam in the horizontal direction. A force F₁ of 2625 N acts at point A where the angle between F, and the x-axis is 100. If force F₂ acts at an angle a = 400 between F2 and the y-axis: (i) Determine the magnitude of F2 necessary to maintain bracket on horizontal equilibrium. (ii) Determine the vertical force at A acting along the y-axis. Give your answers to the…2. A rectangular piece of jello is subjected to simple shear as shown in Fig. 2. (a) Using the expressions for the linear strain tensor, compute the value of the shear strain €12. (b) From €12, calculate the engineering shear strain 12. (c) Compute the average engineering shear strain 712 using the definition of engineer- ing shear strain and compare it with the 12 calculated in (b). A X₂ 150 mm B 3 mm 200 mm 3 mm X₁ Figure 2: A rectangular piece of jello being sheared.