Please write the MySQL query for the following task: Find the first_name, last_name, employee_id, email, salary, department_id and commission_pct of the employee who has the lowest commission_pct under each manager.
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Please write the MySQL query for the following task:
Find the first_name, last_name, employee_id, email, salary, department_id and commission_pct of the employee who has the lowest commission_pct under each manager.
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Solved in 3 steps
- A unique identifier for a data row that consists of more than one field is commonly called a: primary plus key composite primary key foreign key none of the aboveUse the following table to answer the question below: Table name: Customers Column Name Role Data Type Length Constraint customerID stores the ID of a customer Char 5 Primary key custFName stores the first name of a customer Varchar2 35 Cannot be null custLName Stores the last name of a customer Varchar2 35 Cannot be null custGender Store the gender of a customer Char 1 It should be ‘M’ or ‘F’ custDOB Stores the date of birth of a customer Date custIncome Store the income of a customer Number 4 Write a SQL query that displays the number of customers who born on the 16th day of a month . Write in SQL a query that displays the ids of the customers who have the highest income . Create a view named ‘customerDetails’ to hold all the details of customers whose first names start with ‘S’ and their incomes are between 500 and 1000 Omani Rials .Use the following table to answer the questions below: Table name: Customers Column Name Role Data Type Length Constraint customerID stores the ID of a customer Char 5 Primary key custFName stores the first name of a customer Varchar2 35 Cannot be null custLName Stores the last name of a customer Varchar2 35 Cannot be null custGender Store the gender of a customer Char 1 It should be ‘M’ or ‘F’ custDOB Stores the date of birth of a customer Date custIncome Store the income of a customer Number 4 Write in SQL a command that creates the table Customers according to the above description (2 marks). Write in SQL a statement that adds a new column named accountID of type Char(8). This column should be defined as a foreign key that relates the table Customers to the table Account (1.5 marks). Write in SQL a command that deletes the customers whose date of birth is after 22-Dec-1990 (1.5 Marks).…
- Use the following table to answer the questions below: Table name: Customers Column Name Role Data Type Length Constraint customerID stores the ID of a Char 5 Primary key customer custFName stores the first name of a Varchar2 35 Cannot be null customer custLName Stores the last name of a Varchar2 35 Cannot be null customer custGender Store the gender of a Char 1 It should be M customer or 'F' custDOB Stores the date of birth of Date a customer custIncome Store the income of a Number customer a. Write in SQL a command that creates the table Customers according to the above description b. Write in SQL a statement that adds a new column named accountID of type Char(8). This column should be defined as a foreign key that relates the table Customers to the table Account c. Write in SQL a command that deletes the customers whose date of birth is after 22-Dec-1990 d. Write a SQL query that displays the number of customers who born on the 16th day of a month e. Write in SQL a query that…Use the following table to answer the questions below: Table name: Customers Column Name Role Data Type Length Constraint customerID stores the ID of a Char 5 Primary key customer custFName stores the first name of a Varchar2 35 Cannot be null customer custLName Stores the last name of a Varchar2 35 Cannot be null customer custGender Store the gender of a Char 1 It should be M customer or 'F' custDOB Stores the date of birth of Date a customer custIncome Store the income of a Number customer d. Write a SQL query that displays the number of customers who born on the 16th day of a month e. Write in SQL a query that displays the ids of the customers who have the highest income f. Create a view named 'customerDetails' to hold all the details of customers whose first names start with 'S' and their incomes are between 500 and 1000 Omani RialsProblem 1. Using the INVOICE table structure shown in table below do the following: INVOICE Attribute Name Sample Value Sample Value Sample Value Sample Value Sample Value INV_NUM 211347 211347 211347 211348 211349 PROD_NUM AA-E3422QW QD-300932X RU-995748G AA-E3422QW GH-778345P SALE_DATE 15-Jan-2016 15-Jan-2016 15-Jan-2016 15-Jan-2016 16-Jan-2016 PROD_LABEL Rotary sander 0.25-in. drill bit Band saw Rotary sander Power drill VEND_CODE 211 211 309 211 157 VEND_NAME NeverFail, Inc. NeverFail, Inc. BeGood, Inc. NeverFail, Inc. ToughGo, Inc. QUANT_SOLD 1 8 1 2 1 PROD_PRICE $49.95 $3.45 $39.99 $49.95 $87.75 Write the relational schema, draw its dependency diagram, and identify all dependencies, including all partial and transitive dependencies. You can assume that the table does not contain repeating groups and that an invoice number references more than one…
- Use Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.3. In the OrderItems table, display a count of the number of products, grouped by prod_id. Display the count with the alias shown. Sort by prod_id in ascending order. BNBG01 BNBG02 BNBG03 BRO1 BRO2 BRO3 RGANO1 7 rows returned in 0.01 seconds PROD_ID Download 3 3 3 2 1 4 2 NUM_PROD_IDName the candidate keys in the following table: Student L number Student Name Student_SS_Number Student_Address Student City Student State LO005485 Leigh 811-47-4449 5744 KENSINGTON Ave. Boston MD LO004812 Tammy 441-79-7448 30936 OAK Alley Colorado Springs TX LO004415 Alfredo 375-78-2633 5115 BOWEN St. Kansas City VT LO003478 Ramona 360-82-2835 5097 HUBBARD LOWER Blvd. Miami PA LO003058 Crystal 528-16-2635 73192 RANDOLPH SUB Dr. Riverside MD LO004588 Angie 765-16-4433 5115 GROVELAND PARK Dr. Cincinnati FL L0005484 Tonya 410-76-3632 5115 BISHOP FORD Blvd. Irving MS LO003161 Preston 451-47-2634 95289 MONROE Ave. Boston NC HTM B I A - A - I E E E E E X X, E E D T T 12pt Paragraph
- Q2: A-Given the following tables: Student Subject Std_ID 001 002 003 004 Fname Smith Smith Beal Thomson Lname Jolin Susan Fred Marie Std_ID 001 001 002 002 003 Semester 004 Falls03 Spro4 Falls03 C_ID Eng01 Ger01 Eng01 Ger01 Ger01 CSection Spro4 Spro4 Spro4 1. For each table in the database, identify the primary key and the foreign key(s). 2. Do the tables exhibit entity integrity? Explain your answer? 3. Do the tables exhibit referential integrity? Explain your answer? Ita01 ZZZZZZ IN 2N IN 2N IN CName English IN German English German German Italian Grade A B A B A BTable Name Item Column name Constraint Primary key Datatype Varchar2 Varchar2 Varchar2 Size 6 ID ITEM N AME MANUFACTUR ER 30 PRICE Number Not Null DELIVERY DATE Date Varchar2 STATUS 10 Table Name Customer_ Details Column name ID CUSTOMERNAME Datatype Varchar2 Constraint Foreign Key Size Varchar2 Varchar2 30 30 LOCATION CUSTOMERID Varchar2 Number QUAΝΤΙΤΥ Data for Item table ID ΙTEΜ ΑΜΕ MANUFACTURER PRICE DELIΙVERYΥ DAΤΕ STATUS COMPUTER KEYBO ARD COMP UTER COMPUTER 09001 DELL 35000 12-June-2020 PENDING 09002 INTEX 10000 25-June-2020 PENDING COMPL ETED COMPL ETED COMPL ETED 09003 SAMSUNG 32000 18-Feb-2020 09004 LENOVO 37000 о3-Аргil-2020 0900s LAPTOP DELL 57000 20-May-2020 Data for Customer_ Details table ID CUSTOMERNAME CITY CUSTOMERID C0001 C0002 QUANΤITY 525 09001 KALIFA NIZWA 09002 BARKA 8400 09003 09004 SOHAR C0003 C0001 5250 525 NIZWA 09005 BARKA C0004 3150 6. Write an SQL query to display the ID, ITEMNAME, CUSTOMERNAME and price is not equal 35000 and 37000 . 7. Write an SQL query…Create the ROOMS table using the specification below: Table Name: ROOMS Field Name/ Data Type Size Constraints column name RID Number 8 PRIMARY KEY RType Varchar2 25 NOT NULL Rate Number Bedroom Number 5 Room Status Varchar2 10 REFERENCES to CID in Clients Table CID Number
