Please solve Question letter D, the vertical force FD, in N and draw the equivalent systems. Round off the final answers to four decimal places thank youu
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Please solve Question letter D, the vertical force FD, in N and draw the equivalent systems. Round off the final answers to four decimal places thank youu
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- The force-couple system acting at O is equivalent to the wrench acting at A. If R=600i+1400j+700klb and |C|=1200lbft, determine CR.The figure shows one-half of a universal coupling known as the Hooke's joint. The coupling is acted on by the three couples shown: (a) the input couple consisting of forces of magnitude P, (b) the output couple C0, and (c) the couple formed by bearing reactions of magnitude R. If the resultant of these couples is zero, compute R and C0 for P=750lb.The arm ABCD of the industrial robot lies in a vertical plane that is inclined at 40 to the yz-plane. The arm CD makes an angle of 30 with the vertical. A socket wrench attached at point D applies a 52-lb ft couple about the arm CD, directed as shown. (a) Find the couple-vector that represents the given couple. (b) Determine the moment of the couple about the z-axis.
- The tensions in the cables supporting the pole are T1=T2=T3=60kN. Replace the cable tensions with an equivalent force-couple system with the force acting at O. Express your answer in vector form.Difficult Problem: If magnitude of MA is 1200 kN – m and the distance between A and B is 3 m, what is the force FB and distance d so that the system shown at the right is equivalent to a force-couple system acting at point D, where the horizontal component of this force is R = 112 kN to the right and the corresponding couple is 635 counterclockwise. 60 kN 30 50 kN 2 m MA 60° 15° 200 kN m 100 kN 4 m Fs 2 m 200 kN 30 60 kN -3 mA coplanar force system is shown(1)Find the sum of the three forces(2) Reduce the force system to a force-and-couple resultant at O(3) Reduce the force system to a force-and-couple resultant at an arbitrary point A = (x, y)(4) Locate a point on the r-axis at which the force system can be reduced to a single force
- Five forces and a couple act on the plate shown in the figure . - Find the resultant ( R ) Of the four forces , and its angle (e). - Locate it with respect to point ( O). - Show where the resultant cuts both the x - and y- axes. 400KN 7m 1o0 KN 6 m lom 800 KN-m V150 KN 18m 7200KN 100 KN L 8 m4. For the force-couple system as shown, determine the following: Magnitude of the couple moment Mc so that the equivalent system is a single force acting at point P b. a. Point of application of the single equivalent force along line AB if MC is equal to 180 lb-ft counterclockwise. 85 lb 40 ° 100 16 30 lb 15° Mc 35 lb 400 P 1 ft A 85 lb B 1 ft 200 lbQ2: Determine the resultant couple moment of the three couples acting on the plate in figure below. sibi F1=24 N F3=45 N 4 ft F2= 78 N 5 ft 3 't
- F1 F2 a C F3 A F4 D Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = a = 30°, 0 = 60° , B = 30° 2 kN; F4 = 20 kN; F5 = 2 kN; 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m ) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m ) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m ) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate W a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e) 111.1 kN.m ) 151.3 kN.m Go to SettingF1 F2 a F3 A d. F4 Consider the following values: F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 12.7 kN.m c) - 74.6 kN.m d) 52.9 kN.m e) 24.1 kN.m f)- 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) 2.7 kN.m c) 31.6 kN.m d) 8.9 kN.m e) 5.4 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) 51.1 kN.m c) 14.6 kN.m d) 27.9 kN.m e) 74.1 kN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 17.8 kN.m b) 82.7 kN.m c) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m f) 30.1 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m c) 254.6 kN.m d) 93.1 kN.m e) 101.1 kN.m bo200 lb 0 400 lb 3 ft 4 ft (a) 300 lb 2 ft 3 ft y For the loaded plate shown, four parallel forces are applied Three of the 4 forces are shown. The fourth force P and its line of action are unknown. The resultant of this force-couple system is only represented by the couple vector CR=-1100i + 1500j lb.ft. Determine the force P and its line of action. 1. Solve this problem algebraically by hand 2. Write a code to solve it arbitrarily. 3. Use part 2 to verify part 1. 4. In your submission include both just the code plus the "run" version of the code to show the results for P