Please help me implement this C++ function that is supposed to partition the array a into smaller than pivot and others. // f is the beginning of the section to be partitioned // r is the end of the section to be partitioned // return the first slot of the Large section   int partition(int a[], int f, int r)   { int pivot = a[f]; // pivot is the first element int small = f; // small pointer from the left int large = r; // large pointer from the right while (small <= large) //until they cross { // loop for finding out-of-place pairs and swap them // until the small and large cross // you will be checking a[small] and a[large] against pivot // if both are bad (and not crossed yet), swap and then move // if a[small] is OK, move small // if a[large] is OK, move large // TODO: ** } //end of while // return the partition point where // those smaller than pivot are before what is returned // there is a special cases (small is at the beginning) // and a regular case // TODO: }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Question

Please help me implement this C++ function that is supposed to partition the array a into smaller than pivot and others.

// f is the beginning of the section to be partitioned

// r is the end of the section to be partitioned

// return the first slot of the Large section

 

int partition(int a[], int f, int r)   {

int pivot = a[f];

// pivot is the first element

int small = f;

// small pointer from the left

int large = r;

// large pointer from the right

while (small <= large)

//until they cross

{

// loop for finding out-of-place pairs and swap them

// until the small and large cross

// you will be checking a[small] and a[large] against pivot

// if both are bad (and not crossed yet), swap and then move

// if a[small] is OK, move small

// if a[large] is OK, move large

// TODO: **

}

//end of while

// return the partition point where

// those smaller than pivot are before what is returned

// there is a special cases (small is at the beginning)

// and a regular case

// TODO:

}

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