
Chemistry
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ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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please help me find the limiting regent given the data

Transcribed Image Text:### Experiment: Acetanilide Synthesis
#### Materials and Measurements:
1. **Volume of Aniline:** 5.0 mL
2. **Volume of Distilled Water:** 30 mL
3. **Volume of Acetic Anhydride:** 6 mL
4. **Density of Aniline:** 1.06 g/mL
5. **Density of Acetic Anhydride:** 1.080 g/mL
6. **Mass of Recovered Acetanilide:** 6.592 grams
This set of measurements and densities is crucial for the synthesis and recovery processes in the experiment of creating Acetanilide, an important compound in organic chemistry. This data would be used for calculations related to the reaction's yield, purity, and efficiency.
There are no graphs or diagrams provided in this image text. This information serves as a quantitative summary of the reagents used and the product obtained.
![### Determine the Limiting Reagent (Show Working)
**For example... For the reaction:**
\[ A + B \rightarrow C \]
Let's consider the amount of reactant A.
To determine the mole ratio of A, use the following calculation:
\[ \frac{20.00 \text{ g of A} \times 1 \text{ mol of A}}{1 \text{ MW of A}} = \text{mole ratio A} \]
Here, MW represents the Molecular Weight of A.
Thus, it can be represented as:
\[ 20.00 \text{ g of A} \times \left(\frac{1 \text{ mol of A}}{\text{MW of A}}\right) \times \left(\frac{1}{1 \text{ mol of A}}\right) = \text{mole ratio A} \]
By using this method, you can calculate the mole ratio of reactant A in the chemical reaction.](https://content.bartleby.com/qna-images/question/6746fa6f-1856-443b-addc-ecae5d9da9b9/60e6b0e1-599a-40e1-859d-4ee5fe803aec/mr4elfl_thumbnail.jpeg)
Transcribed Image Text:### Determine the Limiting Reagent (Show Working)
**For example... For the reaction:**
\[ A + B \rightarrow C \]
Let's consider the amount of reactant A.
To determine the mole ratio of A, use the following calculation:
\[ \frac{20.00 \text{ g of A} \times 1 \text{ mol of A}}{1 \text{ MW of A}} = \text{mole ratio A} \]
Here, MW represents the Molecular Weight of A.
Thus, it can be represented as:
\[ 20.00 \text{ g of A} \times \left(\frac{1 \text{ mol of A}}{\text{MW of A}}\right) \times \left(\frac{1}{1 \text{ mol of A}}\right) = \text{mole ratio A} \]
By using this method, you can calculate the mole ratio of reactant A in the chemical reaction.
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