Please help me figure out how to get P= Also Identify the conclusion for this hypothesis test. a) Fail to reject H0. There is not sufficient evidence to warrent rejection of the claim that 3% of users develop nausea. b) Reject H0. There is not sufficient evidence to warrent rejection of the claim that 3% of users develop nausea c) Fail to reject H0. There is sufficient evidence to warrent rejection of the claim that 3% of users develop nausea. d) Reject H0. There is sufficient evidence to warrent rejection of the claim that 3% of users develop nausea
Please help me figure out how to get P=
Also Identify the conclusion for this hypothesis test.
a) Fail to reject H0. There is not sufficient evidence to warrent rejection of the claim that 3% of users develop nausea.
b) Reject H0. There is not sufficient evidence to warrent rejection of the claim that 3% of users develop nausea
c) Fail to reject H0. There is sufficient evidence to warrent rejection of the claim that 3% of users develop nausea.
d) Reject H0. There is sufficient evidence to warrent rejection of the claim that 3% of users develop nausea
The test statistic test is -2.16.
The hypothesis is two tailed. The P-value for two tailed test is,
The probability of z less than -2.16 can be obtained using the excel formula “=NORM.S.DIST (-2.16, TRUE)”. The probability value is 0.0153.
The required P-value is,
The P-value for the hypothesis test is 0.031.
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