Please determine based off waveform A)peak amplitude B)peak to peak value C)average value

-) Below are two voltage patterns measured from an oscilloscope. The voltage stage of the CHI probe is 5 V / div, the CH2 probe voltage stage is 10 V / div and the time axis is 2ms / div. According to this information, a) What are the peak to peak and rms voltage values ​​of the voltages in CHI and CH2? b) What is the frequency of the voltages in Hz? c) How many degrees is the phase difference between the two voltages, which voltage is leading?

For the sine wave seen on the oscilloscope screen a -) amplitude B -) peak value c -) Hill to Hill value d -) period E -) frequencyf-)  Find the active (rms) value.

If input voltage is 18Vpeak-peak, plot the output waveform. Assume Ideal approximation.

13. A biased parallel clipper is connected to a squarewave 20VAC input.The biasing voltage of 5V has the same polarity with the Vo while the Si diode is connected in reverse and will conduct only during negative half cycle.

Determine the numerical value of the following accumulations: Problem 03.034.d Accumulator output The numerical value of the given accumulation is 3

The average value of a full-wave rectified voltage with a peak value of 75 Vis a. 53 V b. 47.8 V C. 37.5 V O d. 23.9 V

Why negative peaks are eliminated in Half Wave Rectification and how this can be achieved in Full Wave Rectification without eliminating these peaks?

C. What are the conditions for oscillation?

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