TAgiston - cylindurcontainingheat atairrecirstmperatureinitial volumeinitial pressurefinalConstantanof vo0kpa. TheD.07 m. Peturmineis0.01 m° qthevolumeistheworkSomtion:

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Answered: pirt- Constant of 0kpa. The 0.07 m. Pe!…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q: Prediet the manometer reading after (4.45N) weight is placed between piston f cylinder. on the pan. Assume no leakage or friction Pan 37.5 25mm dia. mm dia. oil 600 mm Szo-92 25mn dia. -Hg CB) 4 Sc) in figurs belew are closed
vout1 =3.33, vout2=3.33, compare between them with the Thevenin theorem?
A tube of length L = 25.0 m that is open at one end contains airthe pressure of an atmosphere. It is pushed vertically into a freshwater lake.until the water rises halfway up the tube, see figure below. Suppose the temperature is the same at all points and does not vary with time. Adopt g=9.8 m/s2.a) What is the depth h of the bottom end of the tube?b) When was work W performed on the (ideal) gas inside the tube?
H.w 3: / carbon dioxide (CO2) has mass (4.2kg) pressure (12 bar) and of If (R temperature (92 0.189 kJ/kg. K)? °C).Calculate the volume %3D
3. Find the Vout and io (a) (b) 20 ka UIS 10 ka ww 6 k2 6 ka 15 V 2V 4 kn 4 ka 1.2 V 10
A thick-wall underwater pipe is placed at 20m below sea level. The pipe is carryingcompressed natural gas with pressure of 50 MPa. The pipe has 115mm outer diameter andmade of 316 stainless steel with yield strength of 205 MPa. The density of sea water could betaken as 1029 kg/m3. Find out:a) What is the resultant outer pressure acting on the underwater pipe? b) What is the minimum inner diameter to ensure the pipe does not yield?c) Sketch the variation of hoop and radial stress across the pipe wall, completed with stresslabelling. d) What is the resultant longitudinal stress of the pipe?
Date: A 60 cm square gate has its fop edge 12 m belaw the water surfa ce. It is on g 45 ang le and iHS bottom edge is hinged as Shown in figure below . What for ce P is needed to just open the gate ? hes O CM 1 8. 10 water ACH 45°
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pirt- Constant of 0kpa. The 0.07 m. Pe! is olution: