Homework Help is Here – Start Your Trial Now!
Science
Physics
When you bend your knee, the quadriceps muscle is stretched. This increases the tension in the quadriceps ten- don attached to your kneecap (patella), which in turn in- creases the tension in the patella tendon that attaches your kneepcap to your lower leg bone (tibia). Simultaneously, the end of your upper leg bone (femur) pushes outward on the patella. In the orientation shown in the figure, the mag- Quadriceps Tendon Femur Patella nitude of the tension in each tendon is 60 N. What is the magnitude of the force being exerted on the patella by the femur in this situation? Assume that the two tendon forces Tibia 42° shown and the force exerted by the femur are the only three forces. (Hint: this image was taken with the person at rest.) Patella Tendon + 60 Here's a free body diagram showing the two tendon forces, with the lower one split into components. Since the image is taken at rest, we need zero net force both vertically and horizontally. That means we need a horizontal component of 60 sin(42) to the right, and a vertical component of 60 – 60 cos(42) pointing down. Calculate those two values, and then use the Pythagorean theorem to combine them as the magnitude of a single vector. 60 sin(42) ' 60 cos(42) The answer is | 43 N

When you bend your knee, the quadriceps muscle is stretched. This increases the tension in the quadriceps ten- don attached to your kneecap (patella), which in turn in- creases the tension in the patella tendon that attaches your kneepcap to your lower leg bone (tibia). Simultaneously, the end of your upper leg bone (femur) pushes outward on the patella. In the orientation shown in the figure, the mag- Quadriceps Tendon Femur Patella nitude of the tension in each tendon is 60 N. What is the magnitude of the force being exerted on the patella by the femur in this situation? Assume that the two tendon forces Tibia 42° shown and the force exerted by the femur are the only three forces. (Hint: this image was taken with the person at rest.) Patella Tendon + 60 Here's a free body diagram showing the two tendon forces, with the lower one split into components. Since the image is taken at rest, we need zero net force both vertically and horizontally. That means we need a horizontal component of 60 sin(42) to the right, and a vertical component of 60 – 60 cos(42) pointing down. Calculate those two values, and then use the Pythagorean theorem to combine them as the magnitude of a single vector. 60 sin(42) ' 60 cos(42) The answer is | 43 N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
icon
Concept explainers
Question

I need help understading this and the calculations step by step 

the answer is in blue 

and i need help how the got 43 n step by step please

When you bend your knee, the quadriceps muscle is stretched. This increases the tension in the quadriceps ten- don attached to your kneecap (patella), which in turn in- creases the tension in the patella tendon that attaches your kneepcap to your lower leg bone (tibia). Simultaneously, the end of your upper leg bone (femur) pushes outward on the patella. In the orientation shown in the figure, the mag- Quadriceps Tendon Femur Patella nitude of the tension in each tendon is 60 N. What is the magnitude of the force being exerted on the patella by the femur in this situation? Assume that the two tendon forces Tibia 42° shown and the force exerted by the femur are the only three forces. (Hint: this image was taken with the person at rest.) Patella Tendon + 60 Here's a free body diagram showing the two tendon forces, with the lower one split into components. Since the image is taken at rest, we need zero net force both vertically and horizontally. That means we need a horizontal component of 60 sin(42) to the right, and a vertical component of 60 – 60 cos(42) pointing down. Calculate those two values, and then use the Pythagorean theorem to combine them as the magnitude of a single vector. 60 sin(42) ' 60 cos(42) The answer is | 43 N
Transcribed Image Text:When you bend your knee, the quadriceps muscle is stretched. This increases the tension in the quadriceps ten- don attached to your kneecap (patella), which in turn in- creases the tension in the patella tendon that attaches your kneepcap to your lower leg bone (tibia). Simultaneously, the end of your upper leg bone (femur) pushes outward on the patella. In the orientation shown in the figure, the mag- Quadriceps Tendon Femur Patella nitude of the tension in each tendon is 60 N. What is the magnitude of the force being exerted on the patella by the femur in this situation? Assume that the two tendon forces Tibia 42° shown and the force exerted by the femur are the only three forces. (Hint: this image was taken with the person at rest.) Patella Tendon + 60 Here's a free body diagram showing the two tendon forces, with the lower one split into components. Since the image is taken at rest, we need zero net force both vertically and horizontally. That means we need a horizontal component of 60 sin(42) to the right, and a vertical component of 60 – 60 cos(42) pointing down. Calculate those two values, and then use the Pythagorean theorem to combine them as the magnitude of a single vector. 60 sin(42) ' 60 cos(42) The answer is | 43 N
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Stress and strain
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS