College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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# Understanding Transverse Waves

## Diagram Analysis

The illustration at the top showcases a series of transverse waves. For an educational understanding, we've labeled crucial points and sections of the wave:

- **a**: Crest - the highest point of the wave.
- **b**: Trough - the lowest point of the wave.
- **c-g**: Other important points for measurement such as wavelength.

## Fill in the Blanks

2. Waves carry **energy** from one place to another.

3. The highest point on a transverse wave is the **crest**, while the lowest part is the **trough**.

4. The **crest** is the height of the wave.

5. The distance from one crest to the next is the **wavelength**.

## Wave Diagram Analysis 

Below the description, a series of wave diagrams labeled A, B, C, and D are presented for analysis:

- **A**: Shows a wave with a moderate amplitude and wavelength.
- **B**: Displays a wave with a larger amplitude.
- **C**: Features shorter wavelengths and higher frequency.
- **D**: Shows a wave with a longer wavelength.

### Questions:

a. Which of the above has the biggest amplitude?  
b. Which of the above has the shortest wavelength?  
c. Which of the above has the longest wavelength?

## Mathematical Relationships

7. Exploration of waves involves understanding relationships:

a. **Period and Frequency**: Mathematically expressed as \( f = \frac{1}{T} \), where \( f \) is frequency and \( T \) is the period.

b. **Wavelength and Frequency**: Inversely proportional, \( v = f \lambda \), where \( v \) is wave speed, \( f \) is frequency, and \( \lambda \) is wavelength.

c. **Wavelength and Period**: Directly proportional, as seen with constant wave speed.

## Problem Solving

8. **Wave Generator Analysis**:

- Consider a generator producing 10 pulses per second. With a wave speed of 300 cm/s:
  
  a. Calculate wavelength:  
     \[
     f = 10 \, \text{Hz}, \, v = 300 \, \text{cm/s}, \, \lambda = \frac{v}{f} = \frac{300}{10} = 30 \, \text{cm}
     \]
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Transcribed Image Text:# Understanding Transverse Waves ## Diagram Analysis The illustration at the top showcases a series of transverse waves. For an educational understanding, we've labeled crucial points and sections of the wave: - **a**: Crest - the highest point of the wave. - **b**: Trough - the lowest point of the wave. - **c-g**: Other important points for measurement such as wavelength. ## Fill in the Blanks 2. Waves carry **energy** from one place to another. 3. The highest point on a transverse wave is the **crest**, while the lowest part is the **trough**. 4. The **crest** is the height of the wave. 5. The distance from one crest to the next is the **wavelength**. ## Wave Diagram Analysis Below the description, a series of wave diagrams labeled A, B, C, and D are presented for analysis: - **A**: Shows a wave with a moderate amplitude and wavelength. - **B**: Displays a wave with a larger amplitude. - **C**: Features shorter wavelengths and higher frequency. - **D**: Shows a wave with a longer wavelength. ### Questions: a. Which of the above has the biggest amplitude? b. Which of the above has the shortest wavelength? c. Which of the above has the longest wavelength? ## Mathematical Relationships 7. Exploration of waves involves understanding relationships: a. **Period and Frequency**: Mathematically expressed as \( f = \frac{1}{T} \), where \( f \) is frequency and \( T \) is the period. b. **Wavelength and Frequency**: Inversely proportional, \( v = f \lambda \), where \( v \) is wave speed, \( f \) is frequency, and \( \lambda \) is wavelength. c. **Wavelength and Period**: Directly proportional, as seen with constant wave speed. ## Problem Solving 8. **Wave Generator Analysis**: - Consider a generator producing 10 pulses per second. With a wave speed of 300 cm/s: a. Calculate wavelength: \[ f = 10 \, \text{Hz}, \, v = 300 \, \text{cm/s}, \, \lambda = \frac{v}{f} = \frac{300}{10} = 30 \, \text{cm} \]
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