A 2000 kg car is driving at a constant speed of 34.9 m/s takes a curve with a 80 m radius. The road is not banked (level road). What is the minimum value of the coefficient of static friction between the tires and the road so that the car can take this curve without slipping? Round your final answer to 1 decimal place. Side note: The speed's value is, in the range of 40 mph to 80 mph, given randomly in the question. If the coefficient of static friction is larger than 1, the car would slip. It is unrealistic to have that high the coefficient of friction in real life. Don't over-speed!

Suppose the coefficient of static and kinetic friction between the road and the tires on a car is 0.60 and 0.30 respectively. The car has no negative lift force. What is the maximum possible speed (in m/s) of the car without slipping as it rounds a flat curve of 32 m radius? Note: write your answer with one decimal place. Answer.

Problem 1. What is the maximum speed with which a 2,000-kg car can round a turn of radius 75.0 m on a flat (horizontal) road if the coefficient of static friction between the tires and the road is 0.600? What angle should the turn be banked to keep the car on the bank at this speed if the coefficient of static friction is changed to 0 (an iey curve)?

A vehicle with a mass of 2.5x103 kg is driving at a speed of 66 km/h around a level roadway with a curvature radius of  56 meters, just staying on the roadway (i.e., driving at the maximum safe speed for this turn and the tire treads). What is the coefficient of friction between the tires and the road? (Hint: Watch your units above.) Answer: μ = __________ (no units)

A curve in a stretch of highway has radius 512 m. The road is unbanked. The coefficient of static friction between the tires and road is 0.700. When the car enters the curve at a speed greater than the maximum safe speed (speed at which the car won’t skid), which of the following statements are correct?

b) The maximum speed that a car can turn a curve of 9.00 m radius without skidding is 70.0 mph (miles per hour). If the coefficient of friction between the tires and the road is 0.600, what is the rated speed of the banked curve? On a wet day, the same car begins to skid on the curve when its speed reaches 60.0 mph. What is the coefficient of friction in this case?   Please answer with complete solution and fre body diagram

Pls help ASAP.

In 1959, Daytona Speed was added to the NASCAR racing circuit and introduced 31° banked curves for racing. This allowed stock cars to reach much higher speeds (around 200 mph) during a race. Today the steepest banked curves are found at Talladega Motor Speed Way at 33° with a turn radius of 1100 ft. The flattest track in NASCAR is Hew Hampshire Motor Speed Way with banked curves of 7° with a turn radius of 410 ft. a) Assuming no friction, what are the max speeds (in mph) without slipping toward the outer edge of the track at the Talladega and NH Motor Speedways? b) With friction (assume μs of 1.1 between the tires and the track)?

A car negotiates an unbanked 81.7 m radius curve at 17.4 m/s.   What would the minimum coefficient of friction be needed to negotiate the curve?

A car drives around two circular curves on two different roads. The two curves have the same radius of curvature. And coincidentally, the maximum speed that the car can drive through either of the turns is the same for both roads. The first road is frictionless, but it is banked at 14.5 degrees from the horizontal. The other turn is flat. What is the coefficient of friction between the car tires and the road on the unbanked turn?