College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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PHYSICS LENS QUESTION
The way in which a converging lens forms the image of an extended
object depends upon where the object is placed with respect to the lens.
Consider the following three possibilities:
• The object is placed further from the lens than its focal point;
• The object is placed at the focal point of the lens;
• The object is placed closer to the lens than its focal point.
For each of these three scenarios, explain, with the aid of a ray diagram,
how the image is formed and what properties it has.
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- Hello, I need help with Q4 and Q5. Thank you!arrow_forwardNeeded to be solved both Question correctly in the order to get positive feedback please provide me hundred percent of Correct solutionarrow_forwardMY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A custom-made compound microscope (see the figure below) with an objective lens with a focal length of 3.55 cm, an eyepiece lens with a focal length of 6.30 cm and a barrel length of 27.5 cm is used to view a 0.100 cm specimen mounted on a microscope slide. Since the microscope is custom-made, it varies slightly from a standard production microscope in that the object distance for the objective is so much larger than the focal length of the objective that we cannot set the object distance for the objective equal to the focal length of the objective. However, the image formed by the objective is close enough to the focal point of the eyepiece that we are justified in setting the object distance for the eyepiece equal to the focal length of the eyepiece. Finally, the microscope is being used by a lab technician with a near point of 33.0 cm. (Use the exact values you enter to make later calculations.) Olp- Objective lens di- Eyepiece lens Object…arrow_forward
- When a converging lens is immersed in water, does it’s focal length increase,decrease or stay the same? Explain I am having a hard time finding this in my textbook, could you help explain this to me? Thank you.arrow_forwardMY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A 1.0 cm-tall object stands in front of a converging lens. It is desired that a virtual image 2.0 times larger than the object be formed by the lens. How far from the lens (in cm) must the object be placed to accomplish this task, if the final image is located 10 cm from the lens? cm Need Help? Read Itarrow_forwardsolve and explain each onearrow_forward
- solve and explain each steparrow_forwardPart 3 - Keplerian Telescope A telescope magnifies far-off images. Rays hitting the objective are almost parallel and are focused to form an inverted, real image at the focal point of the eyepiece. The eyepiece refracts the light so the rays leave the eyepiece again almost parallel. The object remains inverted, and so the angular magnification is defined as M= -B/a, where the angles are shown in Figure 2. objective eyepiece f. f. f. F e F. h inverted image at infinity Figure 2: A Keplerian telescope, invented by Johannes Kepler in 1611, uses two converging lenses as shown. An objective with focal length fo and an eyepiece with focal length fe focus nearly parallel light rays from a distant object into an inverted image of much smaller size than the object. 1. Assume that a and ß are small angles (much less than 1 radian). Using the ray diagram shown in Figure 2 and considering two appropriate triangles, show that M = -fo/ fe.arrow_forward
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