PHP exercise 7  HTML tables involve a lot of repetitive coding - a perfect place to use for loops. You can do even more if you nest the for loops.  In this PHP exercise, use two for loops, one nested inside another. Create the following multiplication table: 1 2 3 4 5 6 7 2 4 6 8 10 12 14 3 6 9 12 15 18 21 4 8 12 16 20 24 28 5 10 15 20 25 30 35 6 12 18 24 30 36 42 7 14 21 28 35 42 49

PHP exercise 7  HTML tables involve a lot of repetitive coding - a perfect place to use for loops. You can do even more if you nest the for loops.  In this PHP exercise, use two for loops, one nested inside another. Create the following multiplication table: 1 2 3 4 5 6 7 2 4 6 8 10 12 14 3 6 9 12 15 18 21 4 8 12 16 20 24 28 5 10 15 20 25 30 35 6 12 18 24 30 36 42 7 14 21 28 35 42 49

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter6: Arrays

Section: Chapter Questions

Problem 14RQ

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Computer Science Build up a web application for product catalogue for a book, Write a PHP program to create a hyper linked list of programming languages covered in that book. By clicking the hyperlink send the user to titles of the text books related to the selected programming languages php code.
I have to check whether the value of each element is equal or greater than the value of the previous element and you had given an array of integers and your task is to write the code in php language
Nearest polygonal number def nearest_polygonal_number(n, s): Any positive integer s > 2 defines an infinite sequence of s-gonal numbers whose i:th element is given by the formula ((s-2)i2 - (s-4)i)/2, as explained on the Wikipedia page "Polygonal Number". In this formula, positions start from 1, not 0, and we use the letter i to denote the position since we will be using the letter n for something else. For example, the sequence of "octagonal numbers" that springs forth from s = 8 starts with 1, 8, 21, 40, 65, 96, 133, 176... Given the number of sides s and an arbitrary integer n, this function should return the s-gonal integer closest to n. If n falls exactly halfway between two s-gonal numbers, return the smaller one. As you can see from the last row of the previous table, this function must be efficient even for gargantuan values of n. The simplest way to make this function efficient is to harness the power of repeated halving to pull your wagon with a clever application of…
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In c++, increment by 1 for each element in a vertical alternating snake pattern Create a two-dimensional array A[10][10] as follows and print it out. 0 00 19 0 0 0 0。。。。 18 20 0 0 000 0 17 21 34 0 000 0 0 12 345678 16 22 33 35 000 0 0 2 19 0 0 0 0 0 0 3 18 20 0 0 0 0 0 4 17 21 34 0 0 0 0 0 5 16 22 33 35 0 0 0 0 6 15 23 32 36 45 0 0 0 7 14 24 31 37 44 46 000 8 13 25 30 38 43 47 52 0 0 9 12 26 29 39 42 48 51 53 0 10 11 27 28 40 41 49 50 54 55 987 6 5 4 3 2 1 0000000005 15 23 32 36 45 00 0 0 14 24 31 37 44 46 0 0 0 13 25 30 38 43 47 52 0 0 9 16 12 26 29 39 42 48 51 53 0 10 11 27 28 40 41 49 50 54 55