Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Perform a bucket sort on a collection L of equal-length strings. Choose a suitable number of buckets (k) and devise a formula to assign a bucket to each of the strings. Trace the list collection for the specified L and k.
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- Can you help me write the code for this one please? Thank youarrow_forwardFill-In Blanks of the following question: At the end of every iteration of gets at the end of the list. Answer: sort the heaviest elementarrow_forwardDefine a collection “ArrayList” to store the students' names. Use a loop to take 5 students’ names from the user and store them in the collection. Add two student names to the collection and remove the last name in the list. Insert a student name in third place in the collection. Sort the names alphabetically. Ask the user to enter a student name and search for it in the collection and prints the result as “Found” or “Not Found”. Print the whole collection using the enhanced for loop. (java)arrow_forward
- Write a version of the binary search algorithm that can be used to search a list of strings. (Use the selection sort that you designed to sort the list.)arrow_forwardThere are two n-element arrays A and B the task is to permute them such that A[i]+b[i]>=k Can someone walk me through the code. I dont understand the iList and jList and why we have if j and i not in List we do List.append. Also at the end why we do if len(iList)+len(jList)==len(A)+len(B) ? def twoArrays (k, A, B): A.sort() B. sort() iList = [] jList = [] for i in range (len (A)): for j in range (len (B)): if(A[i]+B[j]>=k): if j not in jList and i not in iList: iList.append(i) jList.append(j) print (iList) print (jList) if(len (iList) + len(jList) ==len (A) + len(B)) return "YES" else: return "NO"arrow_forwardThe bubble sort algorithm shown in this chapter is less efficientthan it could be. If a pass is made through the list without exchanging any elements, this means that the list is sorted and thereis no reason to continue. Modify this algorithm so that it willstop as soon as it recognizes that the list is sorted. Do not use abreak statementarrow_forward
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