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%3D 3. Given a geometric sequence where a= - 128 and a,= - 512. (a) Using the nth term of a geometric sequence a=a,r" -', substitute for a , and a,. a7 (b) Find - and use this to solve for the first term a=a, and the common ratio r. You can assume r>0. (c) Find a (d) What term in the sequence is -256?

%3D 3. Given a geometric sequence where a= - 128 and a,= - 512. (a) Using the nth term of a geometric sequence a=a,r" -', substitute for a , and a,. a7 (b) Find - and use this to solve for the first term a=a, and the common ratio r. You can assume r>0. (c) Find a (d) What term in the sequence is -256?

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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%3D 3. Given a geometric sequence where a= - 128 and a,= - 512. (a) Using the nth term of a geometric sequence a=a,r" -', substitute for a , and a,. a7 (b) Find - and use this to solve for the first term a=a, and the common ratio r. You can assume r>0. (c) Find a (d) What term in the sequence is -256?
Transcribed Image Text:%3D 3. Given a geometric sequence where a= - 128 and a,= - 512. (a) Using the nth term of a geometric sequence a=a,r" -', substitute for a , and a,. a7 (b) Find - and use this to solve for the first term a=a, and the common ratio r. You can assume r>0. (c) Find a (d) What term in the sequence is -256?
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