PDE.12 d²T Find the most generic solution to the time equation (PDE eqn 17) dt² Note: -v²k²T. Note: since the equation is a second order ODE, you will need two constants. Use a and b for these constants. T(t) = (a(cos(vkt)) + b sin (vkt)) X for the case when the separation constant k is zero. • Remember that your tutorial has Hints in it, at the end of each chapter. If you're stuck, they are often quite useful!

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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PDE.12
d²T
Find the most generic solution to the time equation (PDE eqn 17) dt²
-v²k²T,
Note:
==
for the case when the separation constant k is zero.
Note: since the equation is a second order ODE, you will need two constants. Use a and b for these constants.
T(t) = (a(cos(vkt)) + b sin (vkt))
• Remember that your tutorial has Hints in it, at the end of each chapter. If you're stuck, they are often quite useful!
Transcribed Image Text:PDE.12 d²T Find the most generic solution to the time equation (PDE eqn 17) dt² -v²k²T, Note: == for the case when the separation constant k is zero. Note: since the equation is a second order ODE, you will need two constants. Use a and b for these constants. T(t) = (a(cos(vkt)) + b sin (vkt)) • Remember that your tutorial has Hints in it, at the end of each chapter. If you're stuck, they are often quite useful!
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