passages.† Let W be the total number of words in the passage, S the number of sentences, and L the number of syllables. Then the Flesch test calculates the score F of the passage using the formula F = 206.835 − 1.015w/s-84.6L/w (b) For the rest of this exercise we consider passages that have 20 sentences and 300 syllables. Find a formula expressing F as a function of W for such passages. F = 1/w(206.835w-0.0575w^2-25380) d) What is the maximum number of words in the passages considered in part (b)? (Can there be more words than syllables?) words (e) Bear in mind your answer from part (d), and determine the maximum possible Flesch score F for the passages considered in part (b). Round your ans
passages.† Let W be the total number of words in the passage, S the number of sentences, and L the number of syllables. Then the Flesch test calculates the score F of the passage using the formula F = 206.835 − 1.015w/s-84.6L/w (b) For the rest of this exercise we consider passages that have 20 sentences and 300 syllables. Find a formula expressing F as a function of W for such passages. F = 1/w(206.835w-0.0575w^2-25380) d) What is the maximum number of words in the passages considered in part (b)? (Can there be more words than syllables?) words (e) Bear in mind your answer from part (d), and determine the maximum possible Flesch score F for the passages considered in part (b). Round your ans
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 26PFA
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Topic Video
Question
The Flesch Reading Ease Test is a test that ranks the reading level of passages.† Let W be the total number of words in the passage, S the number of sentences, and L the number of syllables. Then the Flesch test calculates the score F of the passage using the formula
F = 206.835 − 1.015w/s-84.6L/w
(b) For the rest of this exercise we consider passages that have 20 sentences and 300 syllables. Find a formula expressing F as a function of W for such passages.
F = 1/w(206.835w-0.0575w^2-25380)
d) What is the maximum number of words in the passages considered in part (b)? (Can there be more words than syllables?)
words
(e) Bear in mind your answer from part (d), and determine the maximum possible Flesch score F for the passages considered in part (b). Round your answer to the nearest whole number.
F =
words
(e) Bear in mind your answer from part (d), and determine the maximum possible Flesch score F for the passages considered in part (b). Round your answer to the nearest whole number.
F =
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