Particles of the dispersed phase in a colloidal dispersion are A. small enough that they cannot be filtered out using filter paper B. small enough that they cannot be seen by the naked eye C. no correct response D. large enough that they settle out under the influence of gravity E. more than one correct response
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- Which of the ff. statements best describes a colloidal suspension? It consists of solid particles with 0.1 mm diameter. It consists of solid particles with at most 0.1 mm diameter. It consists of solid particles with more than 0.1 mm diameter.# 3 20 E D The molar solubility of aluminum hydroxide in a water solution is Submit Answer 54 $ 888 R F F4 % 5 Retry Entire Group 9 more group attempts remaining T Cengage Learning Cengage Technical Support F5 G A 6 MacBook Air S F6 Y H & 7 V F7 U * 00 8 ▶11 Values it needed for this question. F8 1 9 K F9 O 1 0 J F10 P M. F11 =What TWO things could be done to increase the solubility of a specific gas in solution? esc lock Edit Format Table 12pt v Paragraph Р !! 1 Q A 2 BIU * W S 3 Al E BV T² v 4 R % 5 D F T Ev Ev A 6 G 7 H To 188 O wo * 8
- Which one of the following is incorrect: O a To increase the particle size of the precipitate the relative supersaturation should be maximized. O b. Nucleation means that the precipitate consists of large number of small size particles O c. Digestion is a process in which a precipitate is heated in the presence of solution to improve the purity and filterability O d. In peptization, a coagulated colloid returns to its original dispersed state. O e. Coprecipitation may cause either positive or negative errors.For results/conclusions Using the images attached Write 2 paragraphs 1st paragraph: Starts with Objective. Results of DeltaT and i stated 2nd paragraph: sources of errors discussed The objective is The colligative properties are the properties that undergo a change when a solute is introduced to a solvent. Freezing point depression is also a colligative property. The addition of a solute to a solvent reduces the freezing point of the resulting solution. The freezing point of the solution is always lower than the freezing point of the solvent. This difference in the freezing point between solvent and solution is called freezing point depression. The freezing point depression is directly proportional to the molality of the solution or the number of moles of solute present in the solution.Which of the following sentence is correct: O Reprecipitation usually increases coprecipitated impurities O Digestion is a process in which a precipitate is heated in the presence of solution to improve the purity and filterability OIn peptization, the size of coagulated colloid increased and become stable O Coprecipitation doesn't cause either positive or negative errors O To increase the particle size of the precipitate the relative supersaturation should be maximized.
- Exam card VARIANT 4 1. A solution was obtained by dissolving 25 grams of nonelectrolyte in 1000 grams of water. The freezing temperature for this solution equals as to-1.55 °C. Determine the molar mass of dissolved substance. Cryoscopic constant for water equals to 1.86 K.Kg/mol.- Homework - 2022.pdf - Adobe Acrobat Pro DC (32-bit) Sign Window Help Chapter 14 - Soluti. x 1 / 3 135% 3) Determine the solubility (M) of N2 in water at 25°C if the pressure of N2 is 0.80 atm. The 3). Henry's law constant for nitrogen in water at this temperature is 6.4 x 10-4 M/atm. D) qmu ( (A) aniweb (O (6) aniwenb ( inoituloe arb to yliamb srfl oitulos sds to ulhalonrot stclunle ANITA MSHow many mL of 0.779 M HNO3 are needed to dissolve 5.15 g of BaCO3? esc 1 F1 AAB 2 Q *** F2 W # 3 80 F3 E $ 4 000 000 F4 2HNO3(aq) + BaCO3(s) Ba(NO3)2(aq) + H₂O(l) + CO₂(g) R Cengage Learning | Cengage Technical Support % er oo 5 F5 MacBook Pro T A 6 F6 & 7 Y F7 mL * DII U F8 8 DO 9 1
- The solubility of NaCl is 36.0 g in 100 g of H₂O at 20 °C. What is the maximal amount of NaCl that can dissolve in 200 g of H₂O at 20 °C? rosoft olga gamboa Bobby Offer dge retirement a... of Employ... scaux Cave chemistry Painting and reaction ? 83°F Sunny Bobby Offer of Employ... * 14 f5 -m 16 ard tion 17plz do both with detail explanation plz ...do not give incomplete solutionWhy is potassium hydrogen phthalate (KHP) used to standardize the NaOH solution instead of measuring out a known mass of solid NaOH to be dissolved in water? KHP is an acid and will neutralize some of the NaOH to use later. O There is no reason, NaOH solutions can be used without standardization. O Solid NaOH is hygroscopic and will absorb water, making it virtually impossible to determine a true initial mass and therefore changing the concentration of the solution. Solid NaOH evaporates therefore its concentration can never be known.