Particle A of charge 3.50 ✕ 10−4 C is at the origin, particle B of charge −6.20 ✕ 10−4 C is at (3.64 m, 0) and particle C of charge 1.50 ✕ 10−4 C is at (0, 3.62 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.

Three point charges are placed on the x-y plane: a +25.0 nC charge at the origin, a -25.0 nC charge on the x axis at 10.0 cm, and a +110 nC charge at the point (10.0 cm, 8.00 cm). Find the x component of the total electric force on the +110 nC charge due to the other two. (Express your answer to two significant figures.) Find the y component of the total electric force on the +110 nC charge due to the other two. (Express your answer to two significant figures.) Find the x component of the electric field at the location of the +110 nC charge due to the presence of the other two charges? (Express your answer to two significant figures.) Find the y component of the electric field at the location of the +110 nC charge due to the presence of the other two charges? (Express your answer to two significant figures.)

Particle A of charge 3.00 X Yo-C is at the origin, par- ticle B of charge -6.00 X 10-4 C is at (4.00 m, 0), and particle C of charge 1.00 x 10-4C is at (0, 3.00 m). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B oon C. (d) Calculate the x component of the force exerted by B on C. (e) Calculate the y component of the force exerted by B on C. (f) Sum the two x compo- nents from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. (g) Simi- larly, find the y component of the resultant force vector acting on C. (h) Find the magnitude and direction of the resultant electric force acting on C.

Two particles, one with charge –7.13 × 10-6 C and the other with charge 1.87 × 10-º C, are 0.0659 m apart. What is the magnitude of the force that one particle exerts on the other? magnitude of force: Two new particles with identical positive charge q3 are placed the same 0.0659 m apart. The force between them is measured to be the same as that between the original particles. What is q3 ? 93 = * TOOLS х10°

The figure shows an arrangement of four charged particles, with angle 0 = 31.0 ° and distance d = 3.00 cm. Particle 2 has charge 92 = 6.40 × 10-19 C; particles 3 and 4 have charges q3 = 94 = -1.60 × 10-19 C. (a) What is the distance D between the origin and particle 2 if the net electrostatic force on particle 1 due to the other particles is zero? (b) If particles 3 and 4 were moved closer to the x axis %3D %3D but maintained their symmetry about that axis, would the required value of D be greater than, less than, or the same as in part (a)? 3 D 4

Two point charges are placed as follows: charge q1 = -1.50 nC is at y = +6.00 m and charge q2 = +3.20 nC is at the origin. What is the total force (magnitude and direction) exerted by these two charges on a negative point charge q3 = -5.00 nC located at (2.00 m, -4.00 m)?