Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Please help, I'm stuck on part C and could use an explanation on how to solve it.
![**Missed This?** Read Section 15.2 (Pages 632–636); Watch KCV 15.2, IWE 15.1.
**Consider the following reaction:**
\[ 2 \text{N}_2\text{O} (g) \rightarrow 2 \text{N}_2 (g) + \text{O}_2 (g) \]
---
**Part B**
In the first 13.0 seconds of the reaction, \(1.8 \times 10^{-2} \text{ mol of O}_2\) is produced in a reaction vessel with a volume of 0.310 L. What is the average rate of the reaction over this time interval?
**Express your answer using two significant figures.**
\[ \text{Rate} = 4.5 \times 10^{-3} \, \text{M} \cdot \text{s}^{-1} \]
Submit
Correct ✔️
The average rate of oxygen production was found using the equation:
\[ \text{Rate} = \frac{\Delta [\text{O}_2]}{\Delta t} \]
Where \([\text{O}_2]\) is the concentration of \(\text{O}_2\). Before finding the rate of the reaction, you had to find the concentration of \(\text{O}_2\) by dividing the moles of \(\text{O}_2\) by the volume of the vessel.
---
**Part C**
Predict the rate of change in the concentration of \(\text{N}_2\text{O}\) over this time interval. In other words, what is \(\frac{\Delta [\text{N}_2\text{O}]}{\Delta t}\)?
**Express your answer using two significant figures.**
\[ \frac{\Delta [\text{N}_2\text{O}]}{\Delta t} = \] \(\text{M} \cdot \text{s}^{-1}\)](https://content.bartleby.com/qna-images/question/61b74698-3f34-41c6-b209-082ec83323f3/55697219-016e-454c-a954-2f6b9d8f14aa/1gzeufx_processed.png)
Transcribed Image Text:**Missed This?** Read Section 15.2 (Pages 632–636); Watch KCV 15.2, IWE 15.1.
**Consider the following reaction:**
\[ 2 \text{N}_2\text{O} (g) \rightarrow 2 \text{N}_2 (g) + \text{O}_2 (g) \]
---
**Part B**
In the first 13.0 seconds of the reaction, \(1.8 \times 10^{-2} \text{ mol of O}_2\) is produced in a reaction vessel with a volume of 0.310 L. What is the average rate of the reaction over this time interval?
**Express your answer using two significant figures.**
\[ \text{Rate} = 4.5 \times 10^{-3} \, \text{M} \cdot \text{s}^{-1} \]
Submit
Correct ✔️
The average rate of oxygen production was found using the equation:
\[ \text{Rate} = \frac{\Delta [\text{O}_2]}{\Delta t} \]
Where \([\text{O}_2]\) is the concentration of \(\text{O}_2\). Before finding the rate of the reaction, you had to find the concentration of \(\text{O}_2\) by dividing the moles of \(\text{O}_2\) by the volume of the vessel.
---
**Part C**
Predict the rate of change in the concentration of \(\text{N}_2\text{O}\) over this time interval. In other words, what is \(\frac{\Delta [\text{N}_2\text{O}]}{\Delta t}\)?
**Express your answer using two significant figures.**
\[ \frac{\Delta [\text{N}_2\text{O}]}{\Delta t} = \] \(\text{M} \cdot \text{s}^{-1}\)
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