Part B: Mass of calorimeter = 3.297 g Mass of calorimeter and water = 51.540 g Mass of unkown sample = 5.059 g Initial temperature of water = 19.3 °C Final temperature of water = 26.0 °C

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the mass of the water used? 

What is the total mass of the solution? (water+salt) 

What is the temperature change of the solution? Remember to use the correct sign of delta T. A temperature increase is positive. A temperature decrease is negative.

Calculate the energy absorbed or released by the solution using the temperature change calculated. Use the mass of water plus solid. Assume the same specific heat as water (4.18J/gC). Use the correct sign for q (same sign as the temperature change).

Using the answer above and the mass of unknown, calculate the enthalpy of solution per gram for the unknown? Be sure to use the correct sign.

 

 

Part B:
Mass of calorimeter = 3.297 g
Mass of calorimeter and water = 51.540 g
Mass of unkown sample = 5.059 g
Initial temperature of water = 19.3 °C
Final temperature of water = 26.0 °C
Transcribed Image Text:Part B: Mass of calorimeter = 3.297 g Mass of calorimeter and water = 51.540 g Mass of unkown sample = 5.059 g Initial temperature of water = 19.3 °C Final temperature of water = 26.0 °C
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