Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D.

The beam shown in Figure Q.2 consists of a W610 × 140 structural steel wide-flange shape [E = 200 GPa; I = 1120 × 106 mm4]. If w = 64 kN/m and P = 126 kN , determine: Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load w in the form ??=??????????? Note: EI will cancel out in further calculations. Enter the numerator in the answer box below in kNm3 to three decimal places. Assume the positive direction of deflection in the positive direction of v axis.

The beam shown in Figure Q.2 consists of a W610 x 140 structural steel wide-flange shape [E= 200 GPa;/= 1120 x 106 mm4]. If w= 59 kN/m and P= 129 kN, determine: P A Y, V 1.5 m B W 3.5 m с 2.5 m numerator EI D Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form UB = Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis.

10. A beam is loaded and supported as shown. Determine the components of the reactions at supports A and B.

10. A beam is loaded and supported as shown. Determine the components of the reactions at supports A and B.

A The beam weight is 40 lb/ft. 6 k 1 k/ft A 8' 8' 2' B 180 PROBLEM 4.30 4.31 A beam supports a nonuniformly distributed load as shown. Calculate the reaction at each support. Neglect the weight of the beam. A w = 3 kips/ft w = 7 kips/ft B L = 22'-0" ROBLEM 4.31 2 Calculate the reactions at each support for the beam show Neglect the weight of the beam. 3kN 900 N/m

Problem 2: For the shown beam, 40 N 150 N 250 N knowing that distance d = 1.0 m: a. Calculate the reactions at the supports on the opposite beam. ......

. a-The reaction at fixed end Rcy           b-The bending moment at the fixed end Mc          c- The shear force at B and bending moment at B

The beam shown below is a simple span with an overhang. The beam supports a uniform distributed load. 0.5 kip/ft 16 ft 5 ft 1. Draw a free body diagram (FBD) of the beam and write the equations of equilibrium to solve for the support reactions. You do not have to include the horizontal reaction at A. Answer: RA 3.61 kip ↑, RB 6.89 kip ↑ 2. Draw an FBD of the beam showing the loads and the known magnitude and direction of the support reactions. 3. Draw the shear diagram for the beam. 4. Draw the bending moment diagram for the beam. 5. At what location along the beam does the maximum positive bending moment occur? 6. At what location along the beam does the maximum negative bending moment occur?

Q1. (а) Figure Q1(a) shows a beam loaded with a point load and a partially UTM uniform distributed load. respectively. support at A and B are roller 3 UTM The M 5 UTM (i) Draw the free body diagram of the structure. * UTM UTM Determine the support reactions at A and B by taking the (ii) structure in equilibrium condition. ITM O UTM - UTM 5 UTM O UTM 30kN 30° 10KN/m F = 840 N 2m 24 m 2m 4m A \3 m G UTM 15 m 2 m STMUTM 5 UTM FIGURE Q1(a) 10 ni FIGURE Q1(b) 一