Part A Review Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΕ = 0 Σ Ε = 0 Στο = 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. As shown, a truss is loaded by the forces P₁ = 501 lb and P2 = 210 lb and has the dimension a = 9.50 ft. P₁ B T a/2 C * a/2 H -P₂ E Determine FBC, the magnitude of the force in member BC, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. Express your answer numerically in pounds to three significant figures. ▸ View Available Hint(s) 1 ΑΣΦ Η vec FBC = Submit Part B Complete previous part(s) ? lbs

! Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. At an intersection car B was traveling south and car A was traveling 30° north of east when they slammed into each other. Upon investigation, it was found that after the crash, the two cars got stuck and skidded off at an angle of 10° north of east. Each driver claimed that he was going at the speed limit of 50 km/h and that he tried to slow down, but couldn't avoid the crash because the other driver was going a lot faster. The masses of cars A and B were 1500 kg and 1200 kg, respectively. 10° 30° VR Determine the speed of the faster of the two cars if the slower car was traveling at the speed limit. The speed of the faster car was km/h.

An exponent, such as the 4 in the expression 94, means: the number of times the number before the exponent is multiplied by itself (9 x 9 x 9x 9). O the number of times the number before the exponent is multiplied by 10 (9 x 10 x 10x 10 x 10). O the number to multiply the first number by (9 x 4). O the number of times the digit is written (9999). the number lo add to the first number (9 +4).

Hello, so i have attached two images. the first image is the quetions, i need part b) answered if possible. i have attached my findings to part a) to add to the little information we know to help with part b if needed. Thnks