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Part (a) How many meters are you from your starting point? A numeric answer is expected here. Part (b) What is the compass direction of a line connecting your starting point to your final position?

Part (a) How many meters are you from your starting point? A numeric answer is expected here. Part (b) What is the compass direction of a line connecting your starting point to your final position?

University Physics Volume 1
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 38P: Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far are you from your...
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B) give answers in degrees west of north.
Date: 2/7/2022 Suppose you walk Dw=14 m straight west and then DN= 28 m straight north.
Transcribed Image Text:Date: 2/7/2022 Suppose you walk Dw=14 m straight west and then DN= 28 m straight north.
Part (a) How many meters are you from your starting point? A numeric answer is expected here. Part (b) What is the compass direction of a line connecting your starting point to your final position? C sin() cos() tan() 8. 9. 10IR cotan() asin() аcos() E 4 6. atan() acotan() sinh() 1. cosh() tanh() cotanh() ND Degrees Radians NO CESEACE KERAR Submit I give up! deduction ner feedback
Transcribed Image Text:Part (a) How many meters are you from your starting point? A numeric answer is expected here. Part (b) What is the compass direction of a line connecting your starting point to your final position? C sin() cos() tan() 8. 9. 10IR cotan() asin() аcos() E 4 6. atan() acotan() sinh() 1. cosh() tanh() cotanh() ND Degrees Radians NO CESEACE KERAR Submit I give up! deduction ner feedback
Expert Solution
Step 1

Given to us,

 first walked to west direction 14 m and then 28 m to the north.

 it will form a right angle triangle, thus hypotenuse will be the distance between the initial and final position.

Using Pythagoras theorem,

           Hypotenuse2  = Perpendicular2 + Base2                          = 282 + 142                          = 980Hypotenuse    = 980                          =31.3 m

Thus the distance from initial position is 31.3 m.

 

 

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