Part A Compute the energy released in the fission reaction n+ 239 Pu → 137 Xe+ 100 Zr + 3n Atomic mass of 137 Xe is 136.911562 u, atomic mass of 100 Zr is 99.91776 u, and atomic mass of 239 Pu is 239.052157 u. Express your answer in megaelectron volts. ? ΔΕ MeV

University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter10: Nuclear Physics
Section: Chapter Questions
Problem 45P: (a) Calculate the energy released in the a decay of 238U . (b) What fraction of the mass of a single...
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Part A
Compute the energy released in the fission reaction
n+ 239 Pu → 137 Xe+ 100 Zr + 3n
Atomic mass of 137 Xe is 136.911562 u, atomic mass of 100 Zr is 99.91776 u, and atomic mass of 239 Pu is 239.052157 u.
Express your answer in megaelectron volts.
ΔΕ
MeV
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Transcribed Image Text:Part A Compute the energy released in the fission reaction n+ 239 Pu → 137 Xe+ 100 Zr + 3n Atomic mass of 137 Xe is 136.911562 u, atomic mass of 100 Zr is 99.91776 u, and atomic mass of 239 Pu is 239.052157 u. Express your answer in megaelectron volts. ΔΕ MeV Submit Request Answer
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