Part 2What is VA – VB?VA – VB =iVSave for LaterAttempts: 0 of 4 usedSubmit Answer The electric field in three different wires (I, II, III) made of the same metal, with current flowing in the wires, is shown below. (The restof the circuit, including the battery, is not shown.) The electric field in each wire is: É 1 = É 3 = (0.050, 0, 0) V/m andÉ 2 = (0.800, 0, 0) V/m. Wires I and III have a diameter d1 = 0.005 m, and Wire |l has a diameter d = 1.25 × 10¬3 m. In Wire I,6.19 х 1018electrons flow per second at an average drift speed 3.5 x 10-º m/s.did2dịAВCx=0x=0.5 mx=0.6 mx=1.6 mIIIIII

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Answered: Part 2 What is VA – VB? VA – VB = i V…

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Part 2 What is VA – VB? VA – VB = i V Save for Later Attempts: 0 of 4 used Submit Answer

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter9: Current And Resistance

Section: Chapter Questions

Problem 83CP: A particle accelerator produces a beam with a radius of 1.25 mm with a current of 2.00 mA. Each...

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Question

Part 2
What is VA – VB?
VA – VB =
i
V
Save for Later
Attempts: 0 of 4 used
Submit Answer

The electric field in three different wires (I, II, III) made of the same metal, with current flowing in the wires, is shown below. (The rest
of the circuit, including the battery, is not shown.) The electric field in each wire is: É 1 = É 3 = (0.050, 0, 0) V/m and
É 2 = (0.800, 0, 0) V/m. Wires I and III have a diameter d1 = 0.005 m, and Wire |l has a diameter d = 1.25 × 10¬3 m. In Wire I,
6.19 х 1018
electrons flow per second at an average drift speed 3.5 x 10-º m/s.
di
d2
dị
A
В
C
x=0
x=0.5 m
x=0.6 m
x=1.6 m
I
II
III

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