Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN] Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN]
Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN] Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do I fill in the ICE tables?
![Part 2 - Determining the Equilibrium [Fe(SCN)²+]
3690
:(2)9ms/
TABLE 3
Beaker
A(1)
A(2)
Average A[Fe(SCN)2+]*
AVS A/K
5
0.098
0.088
0.093 2.5x10-5
MS
6
0.154
0.142
0.148
4.01×10-s
7
0-174
8
9
0.178 0.176 4,8×105
0.230 0.232 0.231 6.3 × 10-5
0.291
0.294 0.2925 7.9×10-5
*This is calculated from average A and k from the previous part.
Initial concentrations of iron (III) and thiocyanate ions
*HINT: Use MIV1-M2V2
Total volume in each solution is 20.0 mL
Mi
0.002
TABLE 4
Beaker
[Fe3+]0
[SCN-] 0
5
0.001 2×104
6
0.001 4x164
7
0.001 6×104
8
0.001/8x104
9
0.001 10x104
12
VI
20
10mL
0.002 (2) = m (20)
0.002 (4)
~
SAT
(svods 25 m2)
క
Fill out the following ICE tables to determine the equilibrium constant for each beaker.
*HINTS:
- For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4
- For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3
[Fe(SCN)2+]
- Ke
[Fe3+][SCN]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F954e61b6-2a75-448f-b3f2-ae8fb8d35081%2F0c560cfe-d3f9-415a-aa40-9d4a25cd72b3%2Fi83y24t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part 2 - Determining the Equilibrium [Fe(SCN)²+]
3690
:(2)9ms/
TABLE 3
Beaker
A(1)
A(2)
Average A[Fe(SCN)2+]*
AVS A/K
5
0.098
0.088
0.093 2.5x10-5
MS
6
0.154
0.142
0.148
4.01×10-s
7
0-174
8
9
0.178 0.176 4,8×105
0.230 0.232 0.231 6.3 × 10-5
0.291
0.294 0.2925 7.9×10-5
*This is calculated from average A and k from the previous part.
Initial concentrations of iron (III) and thiocyanate ions
*HINT: Use MIV1-M2V2
Total volume in each solution is 20.0 mL
Mi
0.002
TABLE 4
Beaker
[Fe3+]0
[SCN-] 0
5
0.001 2×104
6
0.001 4x164
7
0.001 6×104
8
0.001/8x104
9
0.001 10x104
12
VI
20
10mL
0.002 (2) = m (20)
0.002 (4)
~
SAT
(svods 25 m2)
క
Fill out the following ICE tables to determine the equilibrium constant for each beaker.
*HINTS:
- For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4
- For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3
[Fe(SCN)2+]
- Ke
[Fe3+][SCN]
![Part 2 - Determining the Equilibrium [Fe(SCN)²+]
3690
:(2)9ms/
TABLE 3
Beaker
A(1)
A(2)
Average A[Fe(SCN)2+]*
AVS A/K
5
0.098
0.088
0.093 2.5x10-5
MS
6
0.154
0.142
0.148
4.01×10-s
7
0-174
8
9
0.178 0.176 4,8×105
0.230 0.232 0.231 6.3 × 10-5
0.291
0.294 0.2925 7.9×10-5
*This is calculated from average A and k from the previous part.
Initial concentrations of iron (III) and thiocyanate ions
*HINT: Use MIV1-M2V2
Total volume in each solution is 20.0 mL
Mi
0.002
TABLE 4
Beaker
[Fe3+]0
[SCN-] 0
5
0.001 2×104
6
0.001 4x164
7
0.001 6×104
8
0.001/8x104
9
0.001 10x104
12
VI
20
10mL
0.002 (2) = m (20)
0.002 (4)
~
SAT
(svods 25 m2)
క
Fill out the following ICE tables to determine the equilibrium constant for each beaker.
*HINTS:
- For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4
- For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3
[Fe(SCN)2+]
- Ke
[Fe3+][SCN]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F954e61b6-2a75-448f-b3f2-ae8fb8d35081%2F0c560cfe-d3f9-415a-aa40-9d4a25cd72b3%2Fck49awi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part 2 - Determining the Equilibrium [Fe(SCN)²+]
3690
:(2)9ms/
TABLE 3
Beaker
A(1)
A(2)
Average A[Fe(SCN)2+]*
AVS A/K
5
0.098
0.088
0.093 2.5x10-5
MS
6
0.154
0.142
0.148
4.01×10-s
7
0-174
8
9
0.178 0.176 4,8×105
0.230 0.232 0.231 6.3 × 10-5
0.291
0.294 0.2925 7.9×10-5
*This is calculated from average A and k from the previous part.
Initial concentrations of iron (III) and thiocyanate ions
*HINT: Use MIV1-M2V2
Total volume in each solution is 20.0 mL
Mi
0.002
TABLE 4
Beaker
[Fe3+]0
[SCN-] 0
5
0.001 2×104
6
0.001 4x164
7
0.001 6×104
8
0.001/8x104
9
0.001 10x104
12
VI
20
10mL
0.002 (2) = m (20)
0.002 (4)
~
SAT
(svods 25 m2)
క
Fill out the following ICE tables to determine the equilibrium constant for each beaker.
*HINTS:
- For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4
- For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3
[Fe(SCN)2+]
- Ke
[Fe3+][SCN]
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