Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN] Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN]
Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN] Part 2 - Determining the Equilibrium [Fe(SCN)²+] 3690 :(2)9ms/ TABLE 3 Beaker A(1) A(2) Average A[Fe(SCN)2+]* AVS A/K 5 0.098 0.088 0.093 2.5x10-5 MS 6 0.154 0.142 0.148 4.01×10-s 7 0-174 8 9 0.178 0.176 4,8×105 0.230 0.232 0.231 6.3 × 10-5 0.291 0.294 0.2925 7.9×10-5 *This is calculated from average A and k from the previous part. Initial concentrations of iron (III) and thiocyanate ions *HINT: Use MIV1-M2V2 Total volume in each solution is 20.0 mL Mi 0.002 TABLE 4 Beaker [Fe3+]0 [SCN-] 0 5 0.001 2×104 6 0.001 4x164 7 0.001 6×104 8 0.001/8x104 9 0.001 10x104 12 VI 20 10mL 0.002 (2) = m (20) 0.002 (4) ~ SAT (svods 25 m2) క Fill out the following ICE tables to determine the equilibrium constant for each beaker. *HINTS: - For the "I" part of the table you will be using the initial concentrations calculated in TABLE 4 - For the "C" part of the table you will be using the Fe(SCN)2+ concentration in TABLE 3 [Fe(SCN)2+] - Ke [Fe3+][SCN]