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part 1,2,3 please

part 1,2,3 please

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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part 1,2,3 please

Step 2 To find where P is increasing, we must decide where P' = 1.7P 1- Assuming that P >0 always, then we need 1 - Therefore, P' is positive whenever PE Submit Skip (you cannot come back) Exercise (b) For what values of P is the population decreasing? Step 1 P is decreasing when P' is negative Step 2 Assuming that P> 0 always, then we need 1 - Therefore, P' is negative whenever PE Submit Skip (you cannot come back) Exercise (c) What are the equilibrium solutions? Step 1 To find where P is decreasing, we must decide where P' = 1.7P1 - 5300 This occurs when P = 0 and when 1 negative P = Equilibrium solutions occur when 0 = P¹ = 1.7P1-. Submit Skip (you cannot come back) P 1.7P(1 - 5300) 5300 > 0. P = 1.7P(1 - 5300) < 0. is positive. . (Enter your answer in interval notation.) 5300 is negative. (Enter your answer in interval notation.) P = 0. What are the all the equilibrium solutions? (Enter your answers as a comma-separated list.) 5300
Transcribed Image Text:Step 2 To find where P is increasing, we must decide where P' = 1.7P 1- Assuming that P >0 always, then we need 1 - Therefore, P' is positive whenever PE Submit Skip (you cannot come back) Exercise (b) For what values of P is the population decreasing? Step 1 P is decreasing when P' is negative Step 2 Assuming that P> 0 always, then we need 1 - Therefore, P' is negative whenever PE Submit Skip (you cannot come back) Exercise (c) What are the equilibrium solutions? Step 1 To find where P is decreasing, we must decide where P' = 1.7P1 - 5300 This occurs when P = 0 and when 1 negative P = Equilibrium solutions occur when 0 = P¹ = 1.7P1-. Submit Skip (you cannot come back) P 1.7P(1 - 5300) 5300 > 0. P = 1.7P(1 - 5300) < 0. is positive. . (Enter your answer in interval notation.) 5300 is negative. (Enter your answer in interval notation.) P = 0. What are the all the equilibrium solutions? (Enter your answers as a comma-separated list.) 5300
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