Introductory Chemistry: A Foundation
9th Edition
ISBN: 9781337399425
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Part 1. Express your answer as an isotope.
Part 2. Express your answer as an isotope.
![The image displays a nuclear equation to solve, with a requirement to express the answer as an isotope. The equation is as follows:
\[ \text{____} \rightarrow \, ^{218}_{86}\text{Rn} + \, ^{4}_{2}\text{He} \]
Users are prompted to express their answer in an input box labeled "Express your answer as an isotope."
Below the input box, there is a checkbox labeled "A chemical reaction does not occur for this question."
Additional options include a "Submit" button for submitting the answer and a "Request Answer" button for assistance.
This setup is typically used for educational purposes in learning environments to test knowledge on nuclear reactions and isotopic expressions.](https://content.bartleby.com/qna-images/question/73d569c5-2e2b-4e09-8501-0d7e6704df3c/7f4d200d-d5b0-4fd7-a7ff-30c0d8fdcbff/p6du15f_processed.png)
Transcribed Image Text:The image displays a nuclear equation to solve, with a requirement to express the answer as an isotope. The equation is as follows:
\[ \text{____} \rightarrow \, ^{218}_{86}\text{Rn} + \, ^{4}_{2}\text{He} \]
Users are prompted to express their answer in an input box labeled "Express your answer as an isotope."
Below the input box, there is a checkbox labeled "A chemical reaction does not occur for this question."
Additional options include a "Submit" button for submitting the answer and a "Request Answer" button for assistance.
This setup is typically used for educational purposes in learning environments to test knowledge on nuclear reactions and isotopic expressions.
![**Nuclear Equation Completion Task**:
The problem involves completing a nuclear equation for the decay of radon, represented as:
\[ \text{Radon-218} \rightarrow \, \_\_ \, + \, \text{Helium-4} \]
**Instructions**:
- Express your answer as an isotope.
**Equation Overview**:
The equation begins with an isotope of radon (Rn) with a mass number of 218 and an atomic number of 86. It decays to produce an unknown product and an alpha particle, which is a helium-4 (\( \text{He} \)) nucleus with a mass number of 4 and an atomic number of 2.
**Input Section**:
- A text input box is provided for you to enter the missing isotope that completes the equation.
- An option is present stating “A chemical reaction does not occur for this question,” meant to clarify that the process involves nuclear decay rather than a chemical reaction.
**Submission**:
- After entering your answer, click “Submit” to check your response.
- If unsure, you can also select “Request Answer” for additional assistance.
**Additional Details**:
In alpha decay, the parent nucleus loses two protons and two neutrons, forming a new element with atomic and mass numbers reduced by 2 and 4, respectively.](https://content.bartleby.com/qna-images/question/73d569c5-2e2b-4e09-8501-0d7e6704df3c/7f4d200d-d5b0-4fd7-a7ff-30c0d8fdcbff/xo2boaq_processed.png)
Transcribed Image Text:**Nuclear Equation Completion Task**:
The problem involves completing a nuclear equation for the decay of radon, represented as:
\[ \text{Radon-218} \rightarrow \, \_\_ \, + \, \text{Helium-4} \]
**Instructions**:
- Express your answer as an isotope.
**Equation Overview**:
The equation begins with an isotope of radon (Rn) with a mass number of 218 and an atomic number of 86. It decays to produce an unknown product and an alpha particle, which is a helium-4 (\( \text{He} \)) nucleus with a mass number of 4 and an atomic number of 2.
**Input Section**:
- A text input box is provided for you to enter the missing isotope that completes the equation.
- An option is present stating “A chemical reaction does not occur for this question,” meant to clarify that the process involves nuclear decay rather than a chemical reaction.
**Submission**:
- After entering your answer, click “Submit” to check your response.
- If unsure, you can also select “Request Answer” for additional assistance.
**Additional Details**:
In alpha decay, the parent nucleus loses two protons and two neutrons, forming a new element with atomic and mass numbers reduced by 2 and 4, respectively.
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