Part: 0/2 Part 1 of 2 Br NaOCH₂CH₂ Draw the alkyl halide in the conformation that is required for an E2 reaction to occur. Use a wedge and dash structure for your answer. 0* 0 Ö
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please show thr conformation and the products formed
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- A certain hydrocarbon had the molecular formula C16H26 and contained two triple bonds. Ozonolysis gave CH3(CH2), CO₂H and HO₂CCH2CH2CH2CH2CO₂H as the only products. Draw a reasonable structure for this hydrocarbon. Click and drag to start drawing a structure. D:Consider the following reaction. Part: 0 / 2 Part 1 of 2 Br NaOCH, CH Draw the alkyl halide in the conformation that is required for an E2 reaction to occur. Use a wedge and dash structure for your answer. Click and drag to start drawing a structure. ☑ :Consider the following reaction. Br Part: 0/2 NaOCH,CH, Draw the alkyl halide in the conformation that is required for an E2 reaction to occur. Use a wedge and dash structure for your answer. Part 1 of 2 Click and drag to start drawing a structure х :☐ G P
- CH=CHNO₂ (2-nitrovinyl)benzene Electrophilic substitution on (2-nitrovinyl)benzene occurs at the meta position. Draw resonance structures to show how the ring is electron-poor at the ortho and para positions. You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate resonance structures using the symbol from the drop-down menu. 0 78 00-F kDraw the line-angle formula of the enol formed in the following alkyne hydration reaction and then draw the structural formula of the carbonyl compound with which this enol is in equilibrium. -C=CH 1. (sia)2BH 2. NaOH/H₂O₂ an enol carbonyl compound • You do not have to consider stereochemistry. • Draw both the enol and the carbonyl forms. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures using the sign from the drop-down menu. ChemDoodleⓇ <Consider the following reaction. NaOCH2CH Draw the alkyl halide in the conformation that is required for an E2 reaction to occur. Use a wedge and dash structure for your answer. X 8:0 G P
- When toluene is treated with sulfuric and nitric acids under special conditions, three nitro (NO2) groups are substituted for hydrogens at the 2, 4 and 6 positions on the ring (the next section discusses why the 2, 4, and 6 positions are substituted). The product is a highly explosive substance called 2,4,6-trinitrotoluene. This subastance is commonly known by a three letter name. What is it?Be sure to answer all parts. Identify the lettered compounds in the following reaction scheme. This reaction was used in the synthesis of a natural product. HC=CCH,OR' HO CH, Li+ PB13 A LOCOR Draw the structures of compounds A, B, and C. Use R for both R and R' in the structures. Only 1 equivalent of alkyne is being used in the reaction. A draw structure ... в draw structure . draw structure .Four alkenes are formed from the E1 reaction of 3-bromo-2,3-dimethylpentane and methanol. Draw the structures of the alkenes and rank them according to the amount that would be formed.
- Draw the major organic product formed by reaction of 2-hexyne with the following reagent: H₂O in H₂SO4 / HgSO4. • Consider E/Z stereochemistry of alkenes. • In cases where there is more than one answer, just draw one. • If no reaction occurs, draw the organic starting material.МЕСНANISMS 1,2-epoxy-1-methylcyclopentane undergoes both acid-catalyzed and base-catalyzed opening of the epoxide ring to form two different products. > Using ethanol as the solvent and an appropriate acid, show the steps in the acid catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). > Using ethanol as the solvent and an appropriate base, show the steps in the base- catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). 1,2-epoxy-1-methylcyclopentane CH3CH=CH₂ CH=CH₂ CH3O O₂N A B Which will be true about the reaction of the two alkenes with HBr? Select the correct response(s): Compound A is more reactive than compound B. CH3O- increases the reactivity of the alkene. N₂O- cause electrons to flow into the ring. CH3O- removes electrons from the ring. Compound B is more reactive than compound A. CH3O- decreases the reactivity of the alkene. and