Parent function is given in RED. In the transformed function (BLUE) point A(4, 2) was transformed into B(-12, 1). Write the transformed function in the form: f(x) = aƒ(b(x + c)) + d 4 B (-12, 1) -12 -10 -2 (0,0) A (4/2) 4 (4, 5) 6 8 10

(1a) Let A = {1, 6, 12}, B = {0, 2, 12}. The following are all relations from A to B, but which are functions? Explain why or why not? f1 = {(1, 2),(6, 0),(12, 12)} f2 = {(1, 0),(1, 2),(6, 12),(12, 0)} f3 = {(1, 12),(6, 0)} f4 = {(1, 0),(6, 0),(12, 2)}   (1b) Let X = {a, b, c, x, y, z} and Y = {1, 2, 3, 4, 5, 6, 7, 8, 9}. Define a function f : X → Y to be: f = {(a, 2),(b, 3),(c, 7),(x, 9),(y, 4),(z, 8)}. Define a function g : Y → X to be: g = {(1, b),(2, c),(3, b),(4, a),(5, z),(6, z),(7, b),(8, x),(9, y)}. Determine the following: 1. The range of f. 2. The range of g. Do we have Rng(f) a proper subset of Codom(f)? What about for g?

Let f=​{(0​,8​),(5​,0​),(9​,4​)}. Find f(0)

A function f is defined by f(x)=2x * 2. Find f-¹1 (-3) Select one: a. 3 O b. C. N/w c/w w O d. 2