P(A or B)=P(A) + P(B) – P(A and B) (a) Is it ever possible that P(A) = 4.3? Explain why or why not. (b) What would need to be true about A and B to ensure that P(A and B) = 0? Justify your answer. Feel free to use create an example probability question where you could define events A and B to help you answer the question.

A and B are events. Use the following data to answer the following questions.  P(A)=0.60 P(B)=0.40 P(B/A)=0.40 P(AC) P(A AND B) P(A OR B)

p(a) =0.36 p(B)=0.50 a( a and b) = 0.2365 find out the probability of p( a or B )

All events are mutually exclusive. Find the probability in question.

Events A and B are independent. Find the missing probability. P(A and B) 5 P(A) = ? 5 11 P(A and B) = 20 143 P(A) = ? 400 P(B) = P(B) = 13 P(B) 20 2 9 P(B) = 20 3 P(A and B) = ? 4 P(A) = Р(A and B) 3D ? P(A) =-

Q13: If A and B are two events such that P(A) = p₁, P(B) = P2, P(ANB) = P3, then the probability that A occurs but B does not occur is: (a) P1 - P3 (b) P1 P2 (c) P1 - P2P3 (d) P1 — P1P2

Events A and B are independent events with P(A) = 0.25 and P(B) = 0.35. The probability of the complement of Event B equals

Write as a decimal

When sent a questionnaire, 50% of the recipients respond immediately. Of those who do not respond immediately, 60% respond when sent a follow-up letter. If the questionnaire is sent to 4 persons and a follow-up letter is sent to any of the 4 who do not respond immediately, what is the probability that at least 3 never respond? A D E (0.2) 4 + 4.(0.2) ³. (0.8) (0.2)4 + 4.(0.2).(0.8)³ (0.4) 4 + 4C (0.4) ³. (0.6) (0.9)4 + 4.(0.9) ³. (0.1) 4.(0.2) ³ (0.8)

Let A and B be two events such that the probability of B is 0.5 and the probability of both is 0.2. Find the probability of A given that B occurs.