P2 657°C Isothermal 2.0 37°C atm V(L) V3 The figure (not to scale) shows a pV diagram for 9.6 g of helium gas (He) that undergoes the process 1→ 2 → 3→1. The ideal gas constant is R = 8.314 J/mol K = 0.0821 L· atm/mol · K, and the atomic weight of helium is 4.0 g/mol. %3D What is the net work done by the gas in Joules? Please give your numerical answer with one decimal place.
P2 657°C Isothermal 2.0 37°C atm V(L) V3 The figure (not to scale) shows a pV diagram for 9.6 g of helium gas (He) that undergoes the process 1→ 2 → 3→1. The ideal gas constant is R = 8.314 J/mol K = 0.0821 L· atm/mol · K, and the atomic weight of helium is 4.0 g/mol. %3D What is the net work done by the gas in Joules? Please give your numerical answer with one decimal place.
Chapter2: The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 81AP: One process for decaffeinating coffee uses carbon dioxide ( M=44.0 g/mol) at a molar density of...
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![P2
657°C
Isothermal
2.0
atm
37°C
0+
V(L)
V3
The figure (not to scale) shows a pV diagram for 9.6 g of helium gas (He) that
undergoes the process 1→ 2 → 3→1. The ideal gas constant is R = 8.314 J/mol .
K = 0.0821 L· atm/mol · K, and the atomic weight of helium is 4.0 g/mol.
%3D
What is the net work done by the gas in Joules?
Please give your numerical answer with one decimal place.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa9e17fc7-257f-41bb-9723-f7b4756fe882%2Fb106fd7e-14e4-4a22-871c-18dadd8b9304%2F7er2dg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P2
657°C
Isothermal
2.0
atm
37°C
0+
V(L)
V3
The figure (not to scale) shows a pV diagram for 9.6 g of helium gas (He) that
undergoes the process 1→ 2 → 3→1. The ideal gas constant is R = 8.314 J/mol .
K = 0.0821 L· atm/mol · K, and the atomic weight of helium is 4.0 g/mol.
%3D
What is the net work done by the gas in Joules?
Please give your numerical answer with one decimal place.
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